今天填一个坑,俄罗斯方块!!
俄罗斯方块的移动不难实现,但是旋转就不太容易实现,究其原因是因为Python中没有数组这种数据结构,所以不能用矩阵的公式。今天把旋转做出来了,刚好整理一下,把之前的都整合在一起
功能:输入字母,打印俄罗斯方块的*图形
# 尽可能吧俄罗斯方块放在中间 Tetris = {'L': [[1, 1], [1, 2], [1, 3], [2, 3]], 'O': [[1, 1], [2, 1], [1, 2], [2, 2]], 'J': [[2, 1], [2, 2], [1, 3], [2, 3]], 'Z': [[1, 1], [2, 1], [2, 2], [3, 2]], 'S': [[1, 1], [1, 2], [2, 2], [2, 3]], 'I': [[1, 1], [1, 2], [1, 3], [1, 4]], 'T': [[1, 1], [2, 1], [2, 2], [3, 1]]} print(Tetris) while True: figure = input("请输入俄罗斯方块的形状") flag = 0 for i in range(0, 5): for j in range(0, 4): for li in range(0, len(Tetris[figure])): # Tetris['L'] if j == Tetris[figure][li][0] and i == Tetris[figure][li][1]: flag = 1 if flag == 1: print("*", end='') else: print(" ", end='') flag = 0 print()
这一版使用了函数+字典
功能:输入字母,打印俄罗斯方块的*图形,输入468可以移动
# 文件名称:Model-Tetris.PY # 开发工具:PyCharm Tetris = {'L': [[1, 1], [1, 2], [1, 3], [2, 3]], 'O': [[1, 1], [2, 1], [1, 2], [2, 2]], 'J': [[2, 1], [2, 2], [1, 3], [2, 3]], 'Z': [[1, 1], [2, 1], [2, 2], [3, 2]], 'S': [[1, 1], [1, 2], [2, 2], [2, 3]], 'I': [[1, 1], [1, 2], [1, 3], [1, 4]], 'T': [[1, 1], [2, 1], [2, 2], [3, 1]]} def L_char(char): flag = 0 for i in range(0, 7): for j in range(0, 7): for li in range(0, len(Tetris[char])): # Tetris['L'] if j == Tetris[char][li][0] and i == Tetris[char][li][1]: flag = 1 if flag == 1: print("*", end='') else: print(" ", end='') flag = 0 print() def move(char, num): if num == 2: for li in range(0, len(Tetris[char])): Tetris[char][li][1] += 1 if num == 4: for li in range(0, len(Tetris[char])): Tetris[char][li][0] -= 1 if num == 6: for li in range(0, len(Tetris[char])): Tetris[char][li][0] += 1 if num == 8: for li in range(0, len(Tetris[char])): Tetris[char][li][1] -= 1
# 文件名称:Test-Tetris.PY # 开发工具:PyCharm from Day05 import Model_Tetris if __name__ == '__main__': char = input("请输入图形:") Model_Tetris.L_char(char) while True: num = int(input("请输入移动代码2/4/6/8:")) if num == 8 or num == 2 or num == 4 or num == 6: Model_Tetris.move(char, num) Model_Tetris.L_char(char) else: break
主要思想:预定义4X4的坐标转换,旋转式查找字典中的转换坐标,进行相应的替换
功能:输入字母,打印俄罗斯方块的*图形,输入468可以移动,输入5可以旋转
废话不多说,直接给出代码:
#!/usr/bin/python # _*_coding:utf-8_*_ # 开发人员:zys # 开发时间:2021/4/16 16:50 # 文件名称:Test-Tetris.PY # 开发工具:PyCharm import random from Day06.test1 import Model_Tetris if __name__ == '__main__': # 随机生成方法 # Character = "LOJSZIT" # char = random.choice(Character) char = "L" Model_Tetris.L_char(char) while True: num = int(input("请输入移动代码4/5/6/8:")) # 5是旋转 if num == 8 or num == 4 or num == 6: Model_Tetris.move(char, num) Model_Tetris.L_char(char) elif num == 5: Model_Tetris.revolve(char) Model_Tetris.L_char(char) else: break
#!/usr/bin/python # _*_coding:utf-8_*_ # 开发人员:zys # 开发时间:2021/4/16 16:36 # 文件名称:Model-Tetris.PY # 开发工具:PyCharm Tetris = {'L': [[1, 1], [1, 2], [1, 3], [2, 3]], 'O': [[1, 1], [1, 2], [2, 1], [2, 2]], 'J': [[1, 2], [2, 2], [3, 1], [3, 2]], 'Z': [[1, 1], [1, 2], [2, 2], [2, 3]], 'S': [[1, 1], [2, 1], [2, 2], [3, 2]], 'I': [[1, 1], [2, 1], [3, 1], [4, 1]], 'T': [[1, 1], [1, 2], [2, 2], [1, 3]]} # 4*4旋转 '''这里补充一个知识点: 字典中的key是不可变的,所以不能用list作为字典的key, 因为list可以修改,这里采用了元组作为key,指明不可改变, 后面地址查值的时候需要进行类型转换。''' rotateDict = {(1, 1): [4, 1], (1, 2): [3, 1], (1, 3): [2, 1], (1, 4): [1, 1], (2, 1): [4, 2], (3, 1): [4, 3], (4, 1): [4, 4], (4, 2): [3, 4], (4, 3): [2, 4], (4, 4): [1, 4], (3, 4): [1, 3], (2, 4): [1, 2], (2, 2): [3, 2], (3, 2): [3, 3], (3, 3): [2, 3], (2, 3): [2, 2]} def L_char(char): flag = 0 for i in range(0, 5): for j in range(0, 5): for li in range(0, len(Tetris[char])): # Tetris['L'] if j == Tetris[char][li][0] and i == Tetris[char][li][1]: flag = 1 if flag == 1: print("*", end='') else: print(" ", end='') flag = 0 print() def move(char, num): if num == 2: for li in range(0, len(Tetris[char])): Tetris[char][li][1] += 1 if num == 4: for li in range(0, len(Tetris[char])): Tetris[char][li][0] -= 1 if num == 6: for li in range(0, len(Tetris[char])): Tetris[char][li][0] += 1 if num == 8: for li in range(0, len(Tetris[char])): Tetris[char][li][1] -= 1 def revolve(char): newTetris = [] # 新的list for i in range(len(Tetris[char])): newTetris.append(rotateDict[tuple(Tetris[char][i])]) # 对应坐标添加到新的坐标 Tetris[char] = newTetris
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