按总提交选择用户

我知道这很简单,但它让我疯狂......

我有一个用户表,评论表和图片表.

我想根据提交的内容排名前10位用户(他们的评论总数和提交的照片).

而已.

惭愧我

更新:基于Ed的回答.

这是我的设置:

users表(user_id,用户名)

图像表(img_id,submittedby_id = users.user_id)

注释表(id,submittedby_id = users.user_id)

和最后的查询:

    select submittedby_id, sum(total)
from 
    (select submittedby_id, count(img_id) as total from    
          images group by submittedby_id 
     union 
     select submittedby_id, count(id) as total from 
          comments group by submittedby_id
    ) as x
 group by submittedby_id 
 order by sum(total) desc limit 10;

Ed Carrel.. 5

也许有点像这样:

select username, sum(submissions) 
from 
    (select username, count(picture_id) from    
          pictures group by username 
     union 
     select username, count(comment_id) from 
          comments group by username
    )
 group by username 
 order by sum(submissions) desc limit 10;

概念性概述:

计算每个表中用户的提交

联合那些,因此每个用户将从子查询中获得0到2个计数.

再组一次,将两个计数相加,然后订购,以便最高金额在最高位置.

希望这可以帮助.

也许有点像这样:

select username, sum(submissions) 
from 
    (select username, count(picture_id) from    
          pictures group by username 
     union 
     select username, count(comment_id) from 
          comments group by username
    )
 group by username 
 order by sum(submissions) desc limit 10;

概念性概述:

计算每个表中用户的提交

联合那些,因此每个用户将从子查询中获得0到2个计数.

再组一次,将两个计数相加,然后订购,以便最高金额在最高位置.

希望这可以帮助.