查询列出SQL Server存储过程以及每个过程的代码行

我想要一个查询,它按名称返回数据库中所有(用户)存储过程的列表,每个存储过程的代码行数.

即

sp_name     lines_of_code
--------    -------------
DoStuff1    120
DoStuff2    50
DoStuff3    30

任何想法如何做到这一点？

select t.sp_name, sum(t.lines_of_code) - 1 as lines_ofcode, t.type_desc
from
(
    select o.name as sp_name, 
    (len(c.text) - len(replace(c.text, char(10), ''))) as lines_of_code,
    case when o.xtype = 'P' then 'Stored Procedure'
    when o.xtype in ('FN', 'IF', 'TF') then 'Function'
    end as type_desc
    from sysobjects o
    inner join syscomments c
    on c.id = o.id
    where o.xtype in ('P', 'FN', 'IF', 'TF')
    and o.category = 0
    and o.name not in ('fn_diagramobjects', 'sp_alterdiagram', 'sp_creatediagram', 'sp_dropdiagram', 'sp_helpdiagramdefinition', 'sp_helpdiagrams', 'sp_renamediagram', 'sp_upgraddiagrams', 'sysdiagrams')
) t
group by t.sp_name, t.type_desc
order by 1

编辑所以它现在也应该在SQL Server 2000-2008中工作,并排除与数据库图相关的sprocs和funcs(看起来像用户创建的对象).

FWIW,这是另一个:

SELECT  o.type_desc AS ROUTINE_TYPE
       ,QUOTENAME(s.[name]) + '.' + QUOTENAME(o.[name]) AS [OBJECT_NAME]
       ,(LEN(m.definition) - LEN(REPLACE(m.definition, CHAR(10), ''))) AS LINES_OF_CODE
FROM    sys.sql_modules AS m
INNER JOIN sys.objects AS o
        ON m.[object_id] = o.[OBJECT_ID]
INNER JOIN sys.schemas AS s
        ON s.[schema_id] = o.[schema_id]