我正在编写一个快速应用程序来查看一个带有一些AJAX样式调用的巨型XML文件viewgroup
.我的问题session['groups']
不是坚持下去.我有一些旧的阵列只有4个成员卡在某处(cookie?..).view
调用时会出现该值.然后,我用最近打开的包含20多个成员的xml文件中的信息覆盖该会话成员.
但是,当viewgroup
调用时,会话变量已恢复为旧值,数组中只有4个成员!
代码后跟输出.注意3个sessionStatus()
电话
def sessionStatus(): print "# of groups in session = " + str(len(session['groups'])) @app.route('/') def index(): cams = [file for file in os.listdir('xml/') if file.lower().endswith('xml')] return render_template('index.html', cam_files=cams) @app.route('/view/') def view(xmlfile): path = 'xml/' + secure_filename(xmlfile) print 'opening ' + path xmlf = open(path, 'r') tree = etree.parse(xmlf) root = tree.getroot() p = re.compile(r'Group') groups = [] for g in root: if (p.search(g.tag) is not None) and (g.attrib['Comment'] != 'Root'): groups.append(Group(g.attrib['Comment'])) sessionStatus() session['groups'] = groups sessionStatus() return render_template('view.html', xml=xmlfile, groups=groups) @app.route('/viewgroup/ ') def viewGroup(name): groups = session['groups'] sessionStatus() if groups is None or len(groups) == 0: raise Exception('invalid group name') groups_filtered = [g for g in groups if g.name == name] if len(groups_filtered) != 1: raise Exception('invalid group name', groups_filtered) group = groups_filtered[0] prop_names = [p.name for p in group.properties] return prop_names
产量
opening xml/d.xml # of groups in session = 5 # of groups in session = 57 127.0.0.1 - - [17/Aug/2011 17:27:29] "GET /view/d.xml HTTP/1.1" 200 - 127.0.0.1 - - [17/Aug/2011 17:27:29] "GET /static/ivtl.css HTTP/1.1" 304 - 127.0.0.1 - - [17/Aug/2011 17:27:29] "GET /static/jquery.js HTTP/1.1" 304 - 127.0.0.1 - - [17/Aug/2011 17:27:29] "GET /static/raphael-min.js HTTP/1.1" 304 - 127.0.0.1 - - [17/Aug/2011 17:27:29] "GET /static/ivtl.css HTTP/1.1" 304 - 127.0.0.1 - - [17/Aug/2011 17:27:29] "GET /favicon.ico HTTP/1.1" 404 - # of groups in session = 5 127.0.0.1 - - [17/Aug/2011 17:27:31] "GET /viewgroup/DeviceInformation HTTP/1.1" 200 -
我需要所有57个团体留下来.任何提示?
数据太大而无法序列化到会话中.现在,我将一个密钥生成一个全局字典并将该密钥存储在会话中.
gXmlData[path] = groups
有一个问题是全球字典将永远存在于越来越多的键,但这个过程并不意味着长寿.