我有一个字符串
string = "firstName:name1, lastName:last1";
现在我需要一个对象obj这样
obj = {firstName:name1, lastName:last1}
我怎么能在JS中这样做？
实际上,最好的解决方案是使用JSON:
文档
JSON.parse(text[, reviver]);
1)
var myobj = JSON.parse('{ "hello":"world" }');
alert(myobj.hello); // 'world'
2)
var myobj = JSON.parse(JSON.stringify({
hello: "world"
});
alert(myobj.hello); // 'world'
3)将函数传递给JSON
var obj = {
hello: "World",
sayHello: (function() {
console.log("I say Hello!");
}).toString()
};
var myobj = JSON.parse(JSON.stringify(obj));
myobj.sayHello = new Function("return ("+myobj.sayHello+")")();
myobj.sayHello();
您的字符串看起来像没有花括号的JSON字符串.
这应该工作:
obj = eval('({' + str + '})');
如果我理解正确:
var properties = string.split(', ');
var obj = {};
properties.forEach(function(property) {
var tup = property.split(':');
obj[tup[0]] = tup[1];
});
我假设属性名称在冒号的左侧,而它所采用的字符串值在右侧.
请注意,这Array.forEach是JavaScript 1.6 - 您可能希望使用工具包以获得最大兼容性.
这个简单的方法......
var string = "{firstName:'name1', lastName:'last1'}";
eval('var obj='+string);
alert(obj.firstName);
产量
name1
如果您使用的是JQuery:
var obj = jQuery.parseJSON('{"path":"/img/filename.jpg"}');
console.log(obj.path); // will print /img/filename.jpg
记住:eval是邪恶的!:d
您需要使用JSON.parse()将String转换为Object:
var obj = JSON.parse('{ "firstName":"name1", "lastName": "last1" }');
如果您有类似的字符串foo: 1, bar: 2，则可以使用以下命令将其转换为有效的obj：
str
.split(',')
.map(x => x.split(':').map(y => y.trim()))
.reduce((a, x) => {
a[x[0]] = x[1];
return a;
}, {});
感谢#javascript中的niggler。
更新说明：
const obj = 'foo: 1, bar: 2'
.split(',') // split into ['foo: 1', 'bar: 2']
.map(keyVal => { // go over each keyVal value in that array
return keyVal
.split(':') // split into ['foo', '1'] and on the next loop ['bar', '2']
.map(_ => _.trim()) // loop over each value in each array and make sure it doesn't have trailing whitespace, the _ is irrelavent because i'm too lazy to think of a good var name for this
})
.reduce((accumulator, currentValue) => { // reduce() takes a func and a beginning object, we're making a fresh object
accumulator[currentValue[0]] = currentValue[1]
// accumulator starts at the beginning obj, in our case {}, and "accumulates" values to it
// since reduce() works like map() in the sense it iterates over an array, and it can be chained upon things like map(),
// first time through it would say "okay accumulator, accumulate currentValue[0] (which is 'foo') = currentValue[1] (which is '1')
// so first time reduce runs, it starts with empty object {} and assigns {foo: '1'} to it
// second time through, it "accumulates" {bar: '2'} to it. so now we have {foo: '1', bar: '2'}
return accumulator
}, {}) // when there are no more things in the array to iterate over, it returns the accumulated stuff
console.log(obj)
令人困惑的MDN文档：
https://developer.mozilla.org/zh-CN/docs/Web/JavaScript/Reference/Global_Objects/Array/map
https://developer.mozilla.org/zh-CN/docs/Web/JavaScript/Reference/Global_Objects/Array/Reduce
演示：http：//jsbin.com/hiduhijevu/edit？js，控制台
功能：
const str2obj = str => {
return str
.split(',')
.map(keyVal => {
return keyVal
.split(':')
.map(_ => _.trim())
})
.reduce((accumulator, currentValue) => {
accumulator[currentValue[0]] = currentValue[1]
return accumulator
}, {})
}
console.log(str2obj('foo: 1, bar: 2')) // see? works!
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