在List中将List拆分为两个子列表的最简单,最标准和/或最有效的方法是什么?改变原始列表是可以的,因此不需要复制.方法签名可以是
/** Split a list into two sublists. The original list will be modified to * have size i and will contain exactly the same elements at indices 0 * through i-1 as it had originally; the returned list will have size * len-i (where len is the size of the original list before the call) * and will have the same elements at indices 0 through len-(i+1) as * the original list had at indices i through len-1. */List split(List list, int i);
[EDIT] List.subList
返回原始列表中的视图,如果修改了原始列表,该视图将变为无效.所以split
不能使用,subList
除非它也省略了原始参考(或者,如在Marc Novakowski的答案中,使用subList
但立即复制结果).
快速半伪代码:
List sub=one.subList(...); List two=new XxxList(sub); sub.clear(); // since sub is backed by one, this removes all sub-list items from one
它使用标准的List实现方法,并避免所有在循环中运行.clear()方法也将使用removeRange()
大多数列表的内部并且效率更高.
您可以使用常用实用程序,例如Guava库:
import com.google.common.collect.Lists; import com.google.common.math.IntMath; import java.math.RoundingMode; int partitionSize = IntMath.divide(list.size(), 2, RoundingMode.UP); List> partitions = Lists.partition(list, partitionSize);
结果是两个列表的列表 - 不完全符合您的规范,但如果需要,您可以轻松地进行调整.
重复使用Marc的解决方案,这个解决方案使用一个for
循环来节省一些调用list.size()
:
List split(List list, int i) { List x = new ArrayList (list.subList(i, list.size())); // Remove items from end of original list for (int j=list.size()-1; j>i; --j) list.remove(j); return x; }