我一直在尝试理解用于Java的BouncyCastle加密API.不幸的是,我发现Java加密通常被服务提供者接口和术语所掩盖,以至于我无法理解实际做的事情.我已经尝试过反复阅读必要的文档,但它只是难以理解,引入了许多远远超出我认为应该需要的概念.
我真正想要的是一个执行以下操作的类:
public class KeyPair { public byte[] public; public byte[] private; } public class RSACrypto { public static KeyPair generateRSAKeyPair() { /*implementation*/} public static byte[] encrypt(byte[] data, byte[] publicKey) { /*impl*/} public static byte[] decrypt(byte[] encryptedData, byte[] privateKey) { /*impl*/ } }
如果这是一个非常复杂的问题,请问"我真正想要的一切".关于在Java加密和BouncyCastle上阅读的地方的任何指示都是非常受欢迎的.任何有关Java加密系统实际布局的概述都非常受欢迎.
import java.security.GeneralSecurityException; import java.security.KeyPair; import java.security.KeyPairGenerator; import java.security.PrivateKey; import java.security.PublicKey; import javax.crypto.Cipher; public class RSACrypto { /* A 1024-bit key will encrypt messages up to 117 bytes long. */ private static final int KEY_SIZE = 1024; private static final String XFORM = "RSA/ECB/OAEPWITHSHA-256ANDMGF1PADDING"; public static KeyPair generateRSAKeyPair() throws GeneralSecurityException { KeyPairGenerator gen = KeyPairGenerator.getInstance("RSA"); gen.initialize(KEY_SIZE); return gen.generateKeyPair(); } public static byte[] encrypt(byte[] plaintext, PublicKey pub) throws GeneralSecurityException { Cipher cipher = Cipher.getInstance(XFORM); cipher.init(Cipher.ENCRYPT_MODE, pub); return cipher.doFinal(plaintext); } public static byte[] decrypt(byte[] ciphertext, PrivateKey pvt) throws GeneralSecurityException { Cipher cipher = Cipher.getInstance(XFORM); cipher.init(Cipher.DECRYPT_MODE, pvt); return cipher.doFinal(ciphertext); } public static void main(String... argv) throws Exception { KeyPair pair = RSACrypto.generateRSAKeyPair(); byte[] plaintext = "A short secret message.".getBytes("UTF-8"); byte[] ciphertext = RSACrypto.encrypt(plaintext, pair.getPublic()); byte[] recovered = RSACrypto.decrypt(ciphertext, pair.getPrivate()); System.out.println(new String(recovered, "UTF-8")); } }