将较近的白色像素组合在一起,并在OpenCV中围绕它们绘制一个矩形

我想将这些相邻的白色像素分组,并使用C++在OpenCV中围绕它们绘制一个矩形.

原始图片:

预期结果:

我是OpenCV的新手.任何帮助将深表感谢.

您可以使用分区根据给定谓词对白色像素进行分组.在这种情况下,您的谓词可以是:对给定欧几里德距离内的所有白色像素进行分组.

然后,您可以计算每个组的边界框,保留最大的框(在下面的RED中),并最终放大它(在下面的绿色中):

码:

#include 
#include 
#include 

using namespace std;
using namespace cv;

int main()
{
    // Load the image 
    Mat3b img = imread("path_to_image", IMREAD_COLOR);

    // Convert to grayscale
    Mat1b gray;
    cvtColor(img, gray, COLOR_BGR2GRAY);

    // Get binary mask (remove jpeg artifacts)
    gray = gray > 200;

    // Get all non black points
    vector pts;
    findNonZero(gray, pts);

    // Define the radius tolerance
    int th_distance = 50; // radius tolerance

    // Apply partition 
    // All pixels within the radius tolerance distance will belong to the same class (same label)
    vector labels;

    // With lambda function (require C++11)
    int th2 = th_distance * th_distance;
    int n_labels = partition(pts, labels, [th2](const Point& lhs, const Point& rhs) {
        return ((lhs.x - rhs.x)*(lhs.x - rhs.x) + (lhs.y - rhs.y)*(lhs.y - rhs.y)) < th2;
    });

    // You can save all points in the same class in a vector (one for each class), just like findContours
    vector> contours(n_labels);
    for (int i = 0; i < pts.size(); ++i)
    {
        contours[labels[i]].push_back(pts[i]);
    }

    // Get bounding boxes
    vector boxes;
    for (int i = 0; i < contours.size(); ++i)
    {
        Rect box = boundingRect(contours[i]);
        boxes.push_back(box);
    }

    // Get largest bounding box
    Rect largest_box = *max_element(boxes.begin(), boxes.end(), [](const Rect& lhs, const Rect& rhs) {
        return lhs.area() < rhs.area();
    });

    // Draw largest bounding box in RED
    Mat3b res = img.clone();
    rectangle(res, largest_box, Scalar(0, 0, 255));

    // Draw enlarged BOX in GREEN
    Rect enlarged_box = largest_box + Size(20,20);
    enlarged_box -= Point(10,10);

    rectangle(res, enlarged_box, Scalar(0, 255, 0));


    imshow("Result", res);
    waitKey();

    return 0;
}