将纬度和经度转换为双值的最简单方法是什么

我有一个包含纬度和经度值的CSV文件,例如:

"25°36'55.57", "E", "45°39'12.52", "N"

任何人都有一个快速而简单的C#代码将其转换为double值？

谢谢

如果你的意思是C#代码:

结果= 25 +(36/60)+(55.57/3600)

首先,您需要使用Regex或其他一些机制解析表达式并将其拆分为单个部分.然后:

String hour = "25";
String minute = "36";
String second = "55.57";
Double result = (hour) + (minute) / 60 + (second) / 3600;

当然,根据N/S或E/S切换到翻转标志.维基百科对此有一点看法:

对于计算,西/半球的后缀由西半球的负号代替.令人困惑的是,有时也会看到对东方负面的惯例.首选的惯例 - 东方是积极的 - 与北极的右手笛卡尔坐标系统一致.然后可以将特定经度与特定纬度(通常在北半球为正)组合以在地球表面上给出精确位置.(http://en.wikipedia.org/wiki/Longitude)

感谢所有快速解答.根据amdfan的回答,我将这段代码放在一起,完成C#中的工作.

/// 
The regular expression parser used to parse the lat/long
private static Regex Parser = new Regex("^(?[-+0-9]+)[^0-9]+(?[0-9]+)[^0-9]+(?[0-9.,]+)[^0-9.,ENSW]+(?[ENSW]*)$");

/// 
Parses the lat lon value.
/// The value.
/// It must have at least 3 parts 'degrees' 'minutes' 'seconds'. If it 
/// has E/W and N/S this is used to change the sign.
/// 
public static double ParseLatLonValue(string value)
{
    // If it starts and finishes with a quote, strip them off
    if (value.StartsWith("\"") && value.EndsWith("\""))
    {
        value = value.Substring(1, value.Length - 2).Replace("\"\"", "\"");
    }

    // Now parse using the regex parser
    Match match = Parser.Match(value);
    if (!match.Success)
    {
        throw new ArgumentException(string.Format(CultureInfo.CurrentUICulture, "Lat/long value of '{0}' is not recognised", value));
    }

    // Convert - adjust the sign if necessary
    double deg = double.Parse(match.Groups["deg"].Value);
    double min = double.Parse(match.Groups["min"].Value);
    double sec = double.Parse(match.Groups["sec"].Value);
    double result = deg + (min / 60) + (sec / 3600);
    if (match.Groups["pos"].Success)
    {
        char ch = match.Groups["pos"].Value[0];
        result = ((ch == 'S') || (ch == 'W')) ? -result : result;
    }
    return result;
}