我正在尝试使用LINQ执行以下SQL,而我最接近的是进行交叉连接和求和计算.我知道必须有一个更好的方法来编写它,所以我转向堆栈团队寻求帮助.
SELECT T1.Column1, T1.Column2, SUM(T3.Column1) AS Amount FROM T1 INNER JOIN T2 ON T1.T1ID = T2.T1ID INNER JOIN T3 ON T2.T3ID = T3.T3ID GROUP BY T1.Column1, T1.Column2
我一直在尝试的是以下LINQ代码
var qTotal = from T2 in context.T2 from T3 in context.T3 where T3.T3ID == T3.T3ID group T3 by T2.T1ID into gT2T3 from T1 in context.T1 where gT2T3.Key.Equals(T1.T1ID) select new { T1.Column1,T1.Column2,Amount = gT2T3.Sum(t => t.Column1)};
我知道必须有一个更好的方法来编写它,我只是不知道如何,任何帮助都会很棒!
试试这个:
var total = from T1 in context.T1 join T2 in context.T2 on T1.T2ID equals T2.T2ID join T3 in context.T3 on T2.T3ID equals T3.T3ID group T3 by new { T1.Column1, T1.Column2 } into g select new { Column1 = T1.Column1, Column2 = T2.Column2, Amount = g.Sum(t3 => t3.Column1) };
对我来说(使用4.0),以下工作.
var total = from T1 in context.T1 join T2 in context.T2 on T1.T2ID equals T2.T2ID join T3 in context.T3 on T2.T3ID equals T3.T3ID group T3 by new { T1.Column1, T1.Column2 } into g select new { Column1 = g.Key.Column1, Column2 = g.Key.Column2, Amount = g.Sum(t3 => t3.Column1) };