你如何做很多表外连接？

我有3个表,foo,foo2bar和bar.foo2bar是foo和bar之间的多对多地图.这是内容.

select * from foo
+------+
| fid  |
+------+
|    1 |
|    2 |
|    3 |
|    4 |
+------+

select * from foo2bar
+------+------+
| fid  | bid  |
+------+------+
|    1 |    1 |
|    1 |    2 |
|    2 |    1 |
|    2 |    3 |
|    4 |    4 |
+------+------+

select * from bar
+------+-------+------+
| bid  | value | zid  |
+------+-------+------+
|    1 |     2 |   10 |
|    2 |     4 |   20 |
|    3 |     8 |   30 |
|    4 |    42 |   30 |
+------+-------+------+

我想要的是,"给我一个包含所有fid和值的列表,其中zid为30"

我期待所有fids的答案,所以结果如下:

+------+--------+
| fid  | value  |
+------+--------+
|    1 |   null |
|    2 |      8 |
|    3 |   null |
|    4 |     42 |
+------+--------+

Bill Karwin.. 17

SELECT * FROM foo
  LEFT OUTER JOIN (foo2bar JOIN bar ON (foo2bar.bid = bar.bid AND zid = 30))
  USING (fid);

在MySQL 5.0.51上测试过.

这不是子查询,它只是使用括号来指定连接的优先级.

SELECT * FROM foo
  LEFT OUTER JOIN (foo2bar JOIN bar ON (foo2bar.bid = bar.bid AND zid = 30))
  USING (fid);

在MySQL 5.0.51上测试过.

这不是子查询,它只是使用括号来指定连接的优先级.

SELECT * FROM
        foo LEFT JOIN
        (
        Foo2bar JOIN bar
             ON foo2bar.bid = bar.bid AND zid = 30
        )
        ON foo.fid = foo2bar.fid;

未经测试