Python有一个用于解析HTTP请求和响应的模块吗？

httplib(现在是http.client)和朋友们都有conn.getresponse()和HTTPResponse类,但是conn.getrequest()和HTTPRequest类的服务器端操作似乎缺乏.

我知道BaseHTTPServer和BaseHTTPRequestHandler可以执行此功能,但它们不会公开这些方法以在模块外部使用.

基本上我想要的是BaseHTTPRequestHandler #parse_request是一个静态方法,它返回一个HTTPRequest对象,而不是填充成员变量.

Jeff,为了启用解析,我创建了一个基本HTTP请求处理程序的小九行子类:

from BaseHTTPServer import BaseHTTPRequestHandler
from StringIO import StringIO

class HTTPRequest(BaseHTTPRequestHandler):
    def __init__(self, request_text):
        self.rfile = StringIO(request_text)
        self.raw_requestline = self.rfile.readline()
        self.error_code = self.error_message = None
        self.parse_request()

    def send_error(self, code, message):
        self.error_code = code
        self.error_message = message

您现在可以在其中包含一个包含HTTP请求文本的字符串,并通过实例化此类来解析它:

# Simply instantiate this class with the request text

request = HTTPRequest(request_text)

print request.error_code       # None  (check this first)
print request.command          # "GET"
print request.path             # "/who/ken/trust.html"
print request.request_version  # "HTTP/1.1"
print len(request.headers)     # 3
print request.headers.keys()   # ['accept-charset', 'host', 'accept']
print request.headers['host']  # "cm.bell-labs.com"

# Parsing can result in an error code and message

request = HTTPRequest('GET\r\nHeader: Value\r\n\r\n')

print request.error_code     # 400
print request.error_message  # "Bad request syntax ('GET')"