R中coord_flip后的反转顺序

dbv的数据示例:

  gender Sektion
1      m       5
2      m       5
3      w      3B
4      w      3B
5      w      3B
6      m       4

我有以下情节:

Sekplot <- ggplot(dbv,aes(x=Sektion,
                          fill=factor(gender),
                          stat="bin", 
                          label = paste(round((..count..)/sum(..count..)*100), "%"))) 
Sekplot <- Sekplot + geom_bar(position="fill")
Sekplot <- Sekplot + scale_y_continuous(labels = percent)
Sekplot <- Sekplot + labs(title = "test")
Sekplot <- Sekplot + scale_fill_discrete(name="test", breaks=c("m", "w", "k.A."), labels=c("m", "w", "k.A."))
Sekplot <- Sekplot + geom_hline(aes(yintercept = ges, linetype = "test"), colour = "black", size = 0.75, show_guide = T)
Sekplot <- last_plot() + coord_flip()
Sekplot <- Sekplot + guides(colour = guide_legend(override.aes = list(linetype = 0 )), 
                                    fill = guide_legend(override.aes = list(linetype = 0 )), 
                                    shape = guide_legend(override.aes = list(linetype = 0 )), 
                                    linetype = guide_legend()) + theme(legend.title=element_blank())

Sekplot 

输出:以错误的顺序绘制y轴

如何反转"Sektion"轴的顺序？我想有一个在顶部,8个在底部.

我尝试过,根据groupA$Date <- factor(groupA$Date, levels=rev(unique(groupA$Date))):

Sekplot <- last_plot() + coord_flip() + scale_x_reverse()

在几种味道,但找不到正确的方法.

您可以scale_x_discrete使用limits参数添加来执行此操作.您可以按照您想要的顺序写出限制,但是当您有许多因子级别时,这会变得复杂.相反,您可以从数据集中提取因子的级别,并利用rev它们以相反的顺序放置它们.

它看起来像: scale_x_discrete(limits = rev(levels(dbv$Sektion)))