如何编写python HTTP服务器来侦听多个端口？

我正在使用BaseHTTPServer和BaseHTTPServer.BaseHTTPRequestHandler的自定义子类在Python中编写一个小型Web服务器.是否可以在多个端口上进行监听？

我现在在做什么:

class MyRequestHandler(BaseHTTPServer.BaseHTTPRequestHandler):
  def doGET
  [...]

class ThreadingHTTPServer(ThreadingMixIn, HTTPServer): 
    pass

server = ThreadingHTTPServer(('localhost', 80), MyRequestHandler)
server.serve_forever()

Eli Courtwri.. 34

当然; 只需在两个不同线程的两个不同端口上启动两个不同的服务器,每个线程使用相同的处理程 这是我刚刚编写和测试的完整,有效的示例.如果您运行此代码,那么您将能够在http:// localhost:1111 /和http:// localhost:2222 /获得Hello World网页

from threading import Thread
from SocketServer import ThreadingMixIn
from BaseHTTPServer import HTTPServer, BaseHTTPRequestHandler

class Handler(BaseHTTPRequestHandler):
    def do_GET(self):
        self.send_response(200)
        self.send_header("Content-type", "text/plain")
        self.end_headers()
        self.wfile.write("Hello World!")

class ThreadingHTTPServer(ThreadingMixIn, HTTPServer):
    daemon_threads = True

def serve_on_port(port):
    server = ThreadingHTTPServer(("localhost",port), Handler)
    server.serve_forever()

Thread(target=serve_on_port, args=[1111]).start()
serve_on_port(2222)

更新:

这也适用于Python 3,但需要稍微更改三行:

from socketserver import ThreadingMixIn
from http.server import HTTPServer, BaseHTTPRequestHandler

和

self.wfile.write(bytes("Hello World!", "utf-8"))

Thomas Vande.. 6

我会说,对这种简单的东西进行线程化是过度的.你最好使用某种形式的异步编程.

以下是使用Twisted的示例:

from twisted.internet import reactor
from twisted.web import resource, server

class MyResource(resource.Resource):
    isLeaf = True
    def render_GET(self, request):
        return 'gotten'

site = server.Site(MyResource())

reactor.listenTCP(8000, site)
reactor.listenTCP(8001, site)
reactor.run()

我还认为以相同的方式处理每个端口看起来更清晰,而不是让主线程处理一个端口而另一个线程处理另一个端口.可以说这可以在线程示例中修复,但是你使用了三个线程.

当然; 只需在两个不同线程的两个不同端口上启动两个不同的服务器,每个线程使用相同的处理程 这是我刚刚编写和测试的完整,有效的示例.如果您运行此代码,那么您将能够在http:// localhost:1111 /和http:// localhost:2222 /获得Hello World网页

from threading import Thread
from SocketServer import ThreadingMixIn
from BaseHTTPServer import HTTPServer, BaseHTTPRequestHandler

class Handler(BaseHTTPRequestHandler):
    def do_GET(self):
        self.send_response(200)
        self.send_header("Content-type", "text/plain")
        self.end_headers()
        self.wfile.write("Hello World!")

class ThreadingHTTPServer(ThreadingMixIn, HTTPServer):
    daemon_threads = True

def serve_on_port(port):
    server = ThreadingHTTPServer(("localhost",port), Handler)
    server.serve_forever()

Thread(target=serve_on_port, args=[1111]).start()
serve_on_port(2222)

更新:

这也适用于Python 3,但需要稍微更改三行:

from socketserver import ThreadingMixIn
from http.server import HTTPServer, BaseHTTPRequestHandler

和

self.wfile.write(bytes("Hello World!", "utf-8"))

我会说,对这种简单的东西进行线程化是过度的.你最好使用某种形式的异步编程.

以下是使用Twisted的示例:

from twisted.internet import reactor
from twisted.web import resource, server

class MyResource(resource.Resource):
    isLeaf = True
    def render_GET(self, request):
        return 'gotten'

site = server.Site(MyResource())

reactor.listenTCP(8000, site)
reactor.listenTCP(8001, site)
reactor.run()

我还认为以相同的方式处理每个端口看起来更清晰,而不是让主线程处理一个端口而另一个线程处理另一个端口.可以说这可以在线程示例中修复,但是你使用了三个线程.

不容易.您可以有两个ThreadingHTTPServer实例,编写自己的serve_forever()函数(不要担心它不是一个复杂的函数).

现有功能:

def serve_forever(self, poll_interval=0.5):
    """Handle one request at a time until shutdown.

    Polls for shutdown every poll_interval seconds. Ignores
    self.timeout. If you need to do periodic tasks, do them in
    another thread.
    """
    self.__serving = True
    self.__is_shut_down.clear()
    while self.__serving:
        # XXX: Consider using another file descriptor or
        # connecting to the socket to wake this up instead of
        # polling. Polling reduces our responsiveness to a
        # shutdown request and wastes cpu at all other times.
        r, w, e = select.select([self], [], [], poll_interval)
        if r:
            self._handle_request_noblock()
    self.__is_shut_down.set()

所以我们的替换将是这样的:

def serve_forever(server1,server2):
    while True:
        r,w,e = select.select([server1,server2],[],[],0)
        if server1 in r:
            server1.handle_request()
        if server2 in r:
            server2.handle_request()