我想输出两个不同的视图(一个作为将作为电子邮件发送的字符串),另一个显示给用户的页面.
这是否可以在ASP.NET MVC beta中使用？
我尝试过多个例子:
1. ASP.NET MVC Beta中的RenderPartial到String
如果我使用此示例,则会收到"在HTTP标头发送后无法重定向".
2. MVC框架:捕获视图的输出
如果我使用它,我似乎无法执行redirectToAction,因为它尝试渲染可能不存在的视图.如果我确实返回了视图,那么它完全搞砸了,看起来根本不正确.
有没有人对我遇到的这些问题有任何想法/解决方案,或者对更好的问题有任何建议？
非常感谢!
以下是一个例子.我要做的是创建GetViewForEmail方法:
public ActionResult OrderResult(string ref)
{
//Get the order
Order order = OrderService.GetOrder(ref);
//The email helper would do the meat and veg by getting the view as a string
//Pass the control name (OrderResultEmail) and the model (order)
string emailView = GetViewForEmail("OrderResultEmail", order);
//Email the order out
EmailHelper(order, emailView);
return View("OrderResult", order);
}
Tim Scott接受的答案(由我改变并格式化):
public virtual string RenderViewToString(
ControllerContext controllerContext,
string viewPath,
string masterPath,
ViewDataDictionary viewData,
TempDataDictionary tempData)
{
Stream filter = null;
ViewPage viewPage = new ViewPage();
//Right, create our view
viewPage.ViewContext = new ViewContext(controllerContext, new WebFormView(viewPath, masterPath), viewData, tempData);
//Get the response context, flush it and get the response filter.
var response = viewPage.ViewContext.HttpContext.Response;
response.Flush();
var oldFilter = response.Filter;
try
{
//Put a new filter into the response
filter = new MemoryStream();
response.Filter = filter;
//Now render the view into the memorystream and flush the response
viewPage.ViewContext.View.Render(viewPage.ViewContext, viewPage.ViewContext.HttpContext.Response.Output);
response.Flush();
//Now read the rendered view.
filter.Position = 0;
var reader = new StreamReader(filter, response.ContentEncoding);
return reader.ReadToEnd();
}
finally
{
//Clean up.
if (filter != null)
{
filter.Dispose();
}
//Now replace the response filter
response.Filter = oldFilter;
}
}
用法示例
假设来自控制器的呼叫获取订单确认电子邮件,则传递Site.Master位置.
string myString = RenderViewToString(this.ControllerContext, "~/Views/Order/OrderResultEmail.aspx", "~/Views/Shared/Site.Master", this.ViewData, this.TempData);
Ben Lesh.. 563
这就是我想出来的,它对我有用.我将以下方法添加到我的控制器基类中.(您可以随时将这些静态方法设置为接受控制器作为参数的其他地方)
MVC2 .ascx风格
protected string RenderViewToString(string viewPath, T model) { ViewData.Model = model; using (var writer = new StringWriter()) { var view = new WebFormView(ControllerContext, viewPath); var vdd = new ViewDataDictionary (model); var viewCxt = new ViewContext(ControllerContext, view, vdd, new TempDataDictionary(), writer); viewCxt.View.Render(viewCxt, writer); return writer.ToString(); } }
剃刀.cshtml风格
public string RenderRazorViewToString(string viewName, object model)
{
ViewData.Model = model;
using (var sw = new StringWriter())
{
var viewResult = ViewEngines.Engines.FindPartialView(ControllerContext,
viewName);
var viewContext = new ViewContext(ControllerContext, viewResult.View,
ViewData, TempData, sw);
viewResult.View.Render(viewContext, sw);
viewResult.ViewEngine.ReleaseView(ControllerContext, viewResult.View);
return sw.GetStringBuilder().ToString();
}
}
编辑:添加了Razor代码.
这就是我想出来的,它对我有用.我将以下方法添加到我的控制器基类中.(您可以随时将这些静态方法设置为接受控制器作为参数的其他地方)
MVC2 .ascx风格
protected string RenderViewToString(string viewPath, T model) { ViewData.Model = model; using (var writer = new StringWriter()) { var view = new WebFormView(ControllerContext, viewPath); var vdd = new ViewDataDictionary (model); var viewCxt = new ViewContext(ControllerContext, view, vdd, new TempDataDictionary(), writer); viewCxt.View.Render(viewCxt, writer); return writer.ToString(); } }
剃刀.cshtml风格
public string RenderRazorViewToString(string viewName, object model)
{
ViewData.Model = model;
using (var sw = new StringWriter())
{
var viewResult = ViewEngines.Engines.FindPartialView(ControllerContext,
viewName);
var viewContext = new ViewContext(ControllerContext, viewResult.View,
ViewData, TempData, sw);
viewResult.View.Render(viewContext, sw);
viewResult.ViewEngine.ReleaseView(ControllerContext, viewResult.View);
return sw.GetStringBuilder().ToString();
}
}
编辑:添加了Razor代码.
这个答案不在我的路上.这最初来自/sf/ask/17360801/, 但在这里我已经展示了将它与"静态"关键字一起使用的方法,使其适用于所有控制器.
为此,你必须static在类文件中创建类.(假设您的类文件名是Utils.cs)
这个例子是For Razor.
Utils.cs
public static class RazorViewToString
{
public static string RenderRazorViewToString(this Controller controller, string viewName, object model)
{
controller.ViewData.Model = model;
using (var sw = new StringWriter())
{
var viewResult = ViewEngines.Engines.FindPartialView(controller.ControllerContext, viewName);
var viewContext = new ViewContext(controller.ControllerContext, viewResult.View, controller.ViewData, controller.TempData, sw);
viewResult.View.Render(viewContext, sw);
viewResult.ViewEngine.ReleaseView(controller.ControllerContext, viewResult.View);
return sw.GetStringBuilder().ToString();
}
}
}
现在,您可以通过将"this"作为参数传递给Controller,在控制器文件中添加NameSpace,从控制器调用此类.
string result = RazorViewToString.RenderRazorViewToString(this ,"ViewName", model);
根据@Sergey给出的建议,这个扩展方法也可以从cotroller调用,如下所示
string result = this.RenderRazorViewToString("ViewName", model);
我希望这对你使代码干净整洁有用.
这对我有用:
public virtual string RenderView(ViewContext viewContext)
{
var response = viewContext.HttpContext.Response;
response.Flush();
var oldFilter = response.Filter;
Stream filter = null;
try
{
filter = new MemoryStream();
response.Filter = filter;
viewContext.View.Render(viewContext, viewContext.HttpContext.Response.Output);
response.Flush();
filter.Position = 0;
var reader = new StreamReader(filter, response.ContentEncoding);
return reader.ReadToEnd();
}
finally
{
if (filter != null)
{
filter.Dispose();
}
response.Filter = oldFilter;
}
}
我发现了一个新的解决方案,可以将视图呈现为字符串,而不必混淆当前HttpContext的响应流(它不允许您更改响应的ContentType或其他标头).
基本上,您所做的就是为视图创建一个假的HttpContext来呈现自己:
///Renders a view to string. public static string RenderViewToString(this Controller controller, string viewName, object viewData) { //Create memory writer var sb = new StringBuilder(); var memWriter = new StringWriter(sb); //Create fake http context to render the view var fakeResponse = new HttpResponse(memWriter); var fakeContext = new HttpContext(HttpContext.Current.Request, fakeResponse); var fakeControllerContext = new ControllerContext( new HttpContextWrapper(fakeContext), controller.ControllerContext.RouteData, controller.ControllerContext.Controller); var oldContext = HttpContext.Current; HttpContext.Current = fakeContext; //Use HtmlHelper to render partial view to fake context var html = new HtmlHelper(new ViewContext(fakeControllerContext, new FakeView(), new ViewDataDictionary(), new TempDataDictionary()), new ViewPage()); html.RenderPartial(viewName, viewData); //Restore context HttpContext.Current = oldContext; //Flush memory and return output memWriter.Flush(); return sb.ToString(); } ///Fake IView implementation used to instantiate an HtmlHelper. public class FakeView : IView { #region IView Members public void Render(ViewContext viewContext, System.IO.TextWriter writer) { throw new NotImplementedException(); } #endregion }
这适用于ASP.NET MVC 1.0,以及ContentResult,JsonResult等.(更改原始HttpResponse上的Headers不会抛出" 服务器无法在发送HTTP标头后设置内容类型 "异常).
更新:在ASP.NET MVC 2.0 RC中,代码有所改变,因为我们必须传入StringWriter用于将视图写入ViewContext:
//...
//Use HtmlHelper to render partial view to fake context
var html = new HtmlHelper(
new ViewContext(fakeControllerContext, new FakeView(),
new ViewDataDictionary(), new TempDataDictionary(), memWriter),
new ViewPage());
html.RenderPartial(viewName, viewData);
//...
本文介绍如何在不同的方案中将视图呈现为字符串:
MVC Controller调用另一个自己的ActionMethods
MVC Controller调用另一个MVC控制器的ActionMethod
WebAPI Controller调用MVC控制器的ActionMethod
解决方案/代码作为名为ViewRenderer的类提供.它是Rick Stahl 在GitHub的WestwindToolkit的一部分.
用法(3. - WebAPI示例):
string html = ViewRenderer.RenderView("~/Areas/ReportDetail/Views/ReportDetail/Index.cshtml", ReportVM.Create(id));
如果你想完全放弃MVC,从而避免所有的HttpContext混乱......
using RazorEngine; using RazorEngine.Templating; // For extension methods. string razorText = System.IO.File.ReadAllText(razorTemplateFileLocation); string emailBody = Engine.Razor.RunCompile(razorText, "templateKey", typeof(Model), model);
这里使用了很棒的开源Razor引擎:https: //github.com/Antaris/RazorEngine
您将使用这种方式获取字符串视图
protected string RenderPartialViewToString(string viewName, object model)
{
if (string.IsNullOrEmpty(viewName))
viewName = ControllerContext.RouteData.GetRequiredString("action");
if (model != null)
ViewData.Model = model;
using (StringWriter sw = new StringWriter())
{
ViewEngineResult viewResult = ViewEngines.Engines.FindPartialView(ControllerContext, viewName);
ViewContext viewContext = new ViewContext(ControllerContext, viewResult.View, ViewData, TempData, sw);
viewResult.View.Render(viewContext, sw);
return sw.GetStringBuilder().ToString();
}
}
我们以两种方式称呼此方法
string strView = RenderPartialViewToString("~/Views/Shared/_Header.cshtml", null)
要么
var model = new Person()
string strView = RenderPartialViewToString("~/Views/Shared/_Header.cshtml", model)
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