如何使用bash或Perl重新格式化mbox文件中的消息？

我有一个巨大的mbox文件,其中可能有500封电子邮件.

它看起来如下:

From x@blah.com Fri Aug 12 09:34:09 2005
Message-ID: <42FBEE81.9090701@blah.com>
Date: Fri, 12 Aug 2005 09:34:09 +0900
From: me 
User-Agent: Mozilla Thunderbird 1.0.6 (Windows/20050716)
X-Accept-Language: en-us, en
MIME-Version: 1.0
To: someone 
Subject: Re: (no subject)
References: 
In-Reply-To: 
Content-Type: text/plain; charset=ISO-8859-1; format=flowed
Content-Transfer-Encoding: 8bit
Status: RO
X-Status: 
X-Keywords:                 
X-UID: 371
X-Evolution-Source: imap://x+blah.com@blah.com/
X-Evolution: 00000002-0010

Hey

the actual content of the email

someone wrote:

> lines of quotedtext

我想知道如何删除所有引用的文本,除去To,From和Date行之外的大部分标题,并且仍然有点连续.

我的目标是能够将这些电子邮件打印成书籍格式,目前每个程序都希望每页打印一封电子邮件,或者所有标题和引用文本.有关从哪里开始使用shell工具制作小程序的任何建议？

Mail :: Box :: Mbox将让您轻松地将文件解析为单独的消息.来自YAPC :: Europe 2002的 Mark Overmeer的幻灯片详细介绍了为什么解析比看起来困难得多.使用这个库还将处理mh,IMAP和许多其他格式,而不仅仅是mbox.

    #!/usr/bin/perl
    use warnings;
    use strict;
    use Mail::Box::Manager;

    my $file = shift || $ENV{MAIL};
    my $mgr = Mail::Box::Manager->new(
        access      => 'r',
    );

    my $folder = $mgr->open( folder => $file )
    or die "$file: Unable to open: $!\n";

    for my $msg ($folder->messages)
    {
        my $to      = join( ', ', map { $_->format } $msg->to );
        my $from    = join( ', ', map { $_->format } $msg->from );
        my $date    = localtime( $msg->timestamp );
        my $subject = $msg->subject;
        my $body    = $msg->body;

        # Strip all quoted text
        $body =~ s/^>.*$//msg;

        print <<"";
    From: $from
    To: $to
    Date: $date
    $body

    }

您可能需要重新考虑删除引用文本的请求 - 如果您使用交错式回复格式化电子邮件,该怎么办？剥离引用的文本会使这种电子邮件很难理解:

  Foo wrote:
  > I like bar.

  Bar?  Who likes bar?

  > It is better than baz.

  Everyone knows that.

  -- 
  Quux

此外,您打算如何处理附件,非文本/纯MIME类型,编码文本实体和其他奇怪的东西？