如何通过cimg获得rgb值？

在Ubuntu 10.04上测试,手工制作的3x3 RGB图像保存为test.png:

sudo apt-get install cimg-dev

源文件cimg_test.cpp:

#include 
using namespace std;

#include 
using namespace cimg_library;

int main()
{
    CImg src("test.png");
    int width = src.width();
    int height = src.height();
    cout << width << "x" << height << endl;
    for (int r = 0; r < height; r++)
        for (int c = 0; c < width; c++)
            cout << "(" << r << "," << c << ") ="
                 << " R" << (int)src(c,r,0,0)
                 << " G" << (int)src(c,r,0,1)
                 << " B" << (int)src(c,r,0,2) << endl;
    return 0;
}

编译并运行:

g++ cimg_test.cpp -lX11 -lpthread -o cimg_test

./cimg_test 
3x3
(0,0) = R0 G0 B0
(0,1) = R255 G0 B0
(0,2) = R0 G255 B0
(1,0) = R0 G0 B255
(1,1) = R128 G128 B128
(1,2) = R0 G0 B128
(2,0) = R128 G0 B0
(2,1) = R0 G128 B0
(2,2) = R255 G255 B255

有用.

在Ubuntu 10.04上测试,手工制作的3x3 RGB图像保存为test.png:

sudo apt-get install cimg-dev

源文件cimg_test.cpp:

#include 
using namespace std;

#include 
using namespace cimg_library;

int main()
{
    CImg src("test.png");
    int width = src.width();
    int height = src.height();
    cout << width << "x" << height << endl;
    for (int r = 0; r < height; r++)
        for (int c = 0; c < width; c++)
            cout << "(" << r << "," << c << ") ="
                 << " R" << (int)src(c,r,0,0)
                 << " G" << (int)src(c,r,0,1)
                 << " B" << (int)src(c,r,0,2) << endl;
    return 0;
}

编译并运行:

g++ cimg_test.cpp -lX11 -lpthread -o cimg_test

./cimg_test 
3x3
(0,0) = R0 G0 B0
(0,1) = R255 G0 B0
(0,2) = R0 G255 B0
(1,0) = R0 G0 B255
(1,1) = R128 G128 B128
(1,2) = R0 G0 B128
(2,0) = R128 G0 B0
(2,1) = R0 G128 B0
(2,2) = R255 G255 B255

有用.