如何在PHP中发出SOAP请求

我试图在PHP中发出SOAP请求.我有我的服务URL,当我在SOAP UI中检查它时,我可以看到以下内容

所以我想用它来登录.目前,我正在尝试以下内容

public function updateApi(){
    $service_url = 'https://someurl.com/sdk/user/session/logon';
    $curl = curl_init($service_url);
    $curl_post_data = array(
        "ApiKey" => 'somekey',
        "ApiSecret" => 'somesecret',
    );
    curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
    curl_setopt($curl, CURLOPT_POST, true);
    curl_setopt($curl, CURLOPT_POSTFIELDS, $curl_post_data);
    $curl_response = curl_exec($curl);
    curl_close($curl);

    var_dump($curl_response);
}

但是,我总是收到登录失败的错误响应.我是否必须调用登录方法或其他什么？真的只是寻找一些关于我是否正确做事的建议.

谢谢

您没有设置Content-Type标题告诉您发布的内容的格式:

curl_setopt($ch, CURLOPT_HTTPHEADER, array(
                      'Content-Type: application/x-www-form-urlencoded'));

否则,从php5以上,http_build_query建议使用:

$curl_post_data = array(
    "ApiKey" => 'somekey',
    "ApiSecret" => 'somesecret',
);

curl_setopt($curl, CURLOPT_POSTFIELDS,
            http_build_query($curl_post_data));

希望它对你有帮助,蒂埃里

根据XML,您应该尝试将curl_post_data变量作为URL编码字符串发送.喜欢urlencode('ApiKey=somekey&ApiSecret=somesecret'),其次尝试将您的请求的内容类型设置为' application/x-www-form-urlencoded'

$service_url = 'https://someurl.com/sdk/user/session/logon';
$curl = curl_init($service_url);
$headers = ["Content-Type: application/json"];  // or other supported media type
$curl_post_data = array(
    "ApiKey" => 'somekey',
    "ApiSecret" => 'somesecret',
);

curl_setopt($curl, CURLOPT_POST, true);
curl_setopt($curl, CURLOPT_POSTFIELDS, $curl_post_data);
curl_setopt($rest, CURLOPT_HTTPHEADER,$headers);  
curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, false);  
curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);  
$curl_response = curl_exec($curl);
curl_close($curl);