如何在Spring JPA中使用一些与SQL兼容的列类型存储Joda Time(any)？

我正在学习如何使用Spring Boot JPA访问数据库.

我用一些实体编写了一个应用程序,其中包含Instant字段:

@Entity
@Table(
   name = "MEAL",
   uniqueConstraints=@UniqueConstraint(columnNames = {"USER_ID", "TIMESTAMP_FIELD"}))
public class Meal {

   //private static DateTimeZone defaultTimeZone = DateTimeZone.UTC;

   @Id
   @GeneratedValue(strategy= GenerationType.AUTO)
   @Column(name = "ID")
   private long id;

   @ManyToOne//(fetch=FetchType.LAZY)
   @JoinColumn(name="USER_ID")
   private User user;

   // @Temporal(TemporalType.TIMESTAMP) if non-Joda time
   //@Type(type = "org.jadira.usertype.dateandtime.joda.PersistentDateTime") 
   @Column(name = "TIMESTAMP_FIELD")
   private Instant timestampField;

我无法编译/运行@Temporal或@Type注释,所以他们被注释掉了.

另外,我无法使用spring.jpa.properties.jadira.usertype.autoRegisterUserTypesin 的设置运行application.properties

这导致了错误

org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in class path resource [org/springframework/boot/autoconfigure/orm/jpa/HibernateJpaAutoConfiguration.class]: Invocation of init method failed; nested exception is java.lang.NoSuchMethodError: org.hibernate.cfg.Configuration.registerTypeOverride(Lorg/hibernate/usertype/UserType;[Ljava/lang/String;)Lorg/hibernate/cfg/Configuration;

所以,这一行也被注释掉了.

spring.datasource.url=jdbc:h2:tcp://localhost/~/pdk
spring.datasource.username=sa
spring.datasource.password=
spring.datasource.driver-class-name=org.h2.Driver

# Jadira requirement
#spring.jpa.properties.jadira.usertype.autoRegisterUserTypes=true

不幸的是,在最终状态下,我在字段内容中获得了一些序列化/二进制数据

这里有可能有一些SQL兼容的列类型吗？

UPDATE

我发现,以下注释工作正常:

@Type(type = "org.jadira.usertype.dateandtime.joda.PersistentInstantAsTimestamp")

但为什么设置application.properties不起作用？