SQL Server将整数转换为二进制字符串

我想知道在SQL中是否有一种简单的方法可以将整数转换为二进制表示形式,然后将其存储为varchar.

例如,5将转换为"101"并存储为varchar.

1> Sean..：

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以下可以编码为函数.您需要修剪前导零以满足您的问题要求.

declare @intvalue int
set @intvalue=5

declare @vsresult varchar(64)
declare @inti int
select @inti = 64, @vsresult = ''
while @inti>0
  begin
    select @vsresult=convert(char(1), @intvalue % 2)+@vsresult
    select @intvalue = convert(int, (@intvalue / 2)), @inti=@inti-1
  end
select @vsresult

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这是一个非常糟糕的解决方案。（1）无需使用任何循环（2）无需进行任何复杂的数学运算，例如为每个幂计算Modulo 2。 .info / Blog / tabid / 83 / EntryId / 169 / T-SQL-Converting-between小数位二进制和十六进制.aspx

2> Mathew Frank..：

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实际上,使用普通的旧SQL非常简单.只需使用按位AND.我有点惊讶的是,没有一个简单的解决方案在线发布(没有调用UDF).在我的情况下,我真的想检查位是打开还是关闭(数据来自dotnet eNums).

因此,这里有一个例子,它将单独和一起给你 - 位值和二进制字符串(大联盟只是一种产生数字的hacky方式,可以在DBs上工作:

    select t.Number
    , cast(t.Number & 64 as bit) as bit7
    , cast(t.Number & 32 as bit) as bit6
    , cast(t.Number & 16 as bit) as bit5
    , cast(t.Number & 8 as bit) as bit4
    , cast(t.Number & 4 as bit) as bit3
    , cast(t.Number & 2 as bit)  as bit2
    ,cast(t.Number & 1 as bit) as bit1

    , cast(cast(t.Number & 64 as bit) as CHAR(1)) 
    +cast( cast(t.Number & 32 as bit) as CHAR(1))
    +cast( cast(t.Number & 16 as bit)  as CHAR(1))
    +cast( cast(t.Number & 8 as bit)  as CHAR(1))
    +cast( cast(t.Number & 4 as bit)  as CHAR(1))
    +cast( cast(t.Number & 2 as bit)   as CHAR(1))
    +cast(cast(t.Number & 1 as bit)  as CHAR(1)) as binary_string
    --to explicitly answer the question, on MSSQL without using REGEXP (which would make it simple)
    ,SUBSTRING(cast(cast(t.Number & 64 as bit) as CHAR(1)) 
                    +cast( cast(t.Number & 32 as bit) as CHAR(1))
                    +cast( cast(t.Number & 16 as bit)  as CHAR(1))
                    +cast( cast(t.Number & 8 as bit)  as CHAR(1))
                    +cast( cast(t.Number & 4 as bit)  as CHAR(1))
                    +cast( cast(t.Number & 2 as bit)   as CHAR(1))
                    +cast(cast(t.Number & 1 as bit)  as CHAR(1))
                    ,
                    PATINDEX('%1%', cast(cast(t.Number & 64 as bit) as CHAR(1)) 
                                        +cast( cast(t.Number & 32 as bit) as CHAR(1))
                                        +cast( cast(t.Number & 16 as bit)  as CHAR(1))
                                        +cast( cast(t.Number & 8 as bit)  as CHAR(1))
                                        +cast( cast(t.Number & 4 as bit)  as CHAR(1))
                                        +cast( cast(t.Number & 2 as bit)   as CHAR(1))
                                        +cast(cast(t.Number & 1 as bit)  as CHAR(1)  )
                    )
,99)


from (select 1 as Number union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 
    union all select 7 union all select 8 union all select 9 union all select 10) as t

产生这个结果:

num  bit7 bit6 bit5 bit4 bit3 bit2 bit1 binary_string   binary_string_trimmed 
1    0    0    0    0    0    0    1    0000001         1
2    0    0    0    0    0    1    0    0000010         10
3    0    0    0    0    0    1    1    0000011         11
4    0    0    0    1    0    0    0    0000100         100
5    0    0    0    0    1    0    1    0000101         101
6    0    0    0    0    1    1    0    0000110         110
7    0    0    0    0    1    1    1    0000111         111
8    0    0    0    1    0    0    0    0001000         1000
9    0    0    0    1    0    0    1    0001001         1001
10   0    0    0    1    0    1    0    0001010         1010

3> Milox..：

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这是一个通用的基本转换器

http://dpatrickcaldwell.blogspot.com/2009/05/converting-decimal-to-hexadecimal-with.html

你可以做

select reverse(dbo.ConvertToBase(5, 2))   -- 101