Scala语法 - 将字符串传递给对象

在Scala中使用regexp时我写了这样的东西:

scala> val y = "Foo"
y: java.lang.String = Foo

scala> y "Bar"

scala>

如您所见,第二个语句只是默默接受.这是合法的法律声明,如果是,它会做什么？或者它是解析器中的错误,应该有错误消息？

这确实是解析器中的错误.它在scala 2.7.2(目前是RC6)中修复

$ ./scala
Welcome to Scala version 2.7.2.RC6 (Java HotSpot(TM) Client VM, Java 1.5.0_16).
Type in expressions to have them evaluated.
Type :help for more information.
scala> def y = "foo"
y: java.lang.String

scala> y "bar"
:1: error: ';' expected but string literal found.
       y "bar"
         ^

scala> val x = "foo"
x: java.lang.String = foo

scala> x "foo"
:1: error: ';' expected but string literal found.
       x "foo"
         ^

scala> "foo" "bar"
:1: error: ';' expected but string literal found.
       "foo" "bar"
             ^