是否有简单的方法来连接两个RouteValueDictionary值以将参数传递给Html.ActionLink

查看我在部分视图中创建的代码:

            <% foreach (Customer customerInfo in Model.DataRows) {%>

            
                
                    <%=Html.ActionLink(
                            customerInfo.FullName
                            , ((string)ViewData["ActionNameForSelectedCustomer"])
                            , JoinParameters(customerInfo.id, (RouteValueDictionary) ViewData["AdditionalSelectionParameters"])
                            , null)%>
                
                
                    <%=customerInfo.LegalGuardianName %>
                
                
                    <%=customerInfo.HomePhone %>
                
                
                    <%=customerInfo.CellPhone %>
                
            
            <%}%>

    private RouteValueDictionary JoinParameters(int customerId, RouteValueDictionary defaultValues)
    {
        RouteValueDictionary routeValueDictionary = new RouteValueDictionary(defaultValues);

        routeValueDictionary.Add("customerId", customerId);

        return routeValueDictionary;                               
    }
...script...

            <% foreach (Customer customerInfo in Model.DataRows) {%>

            
                
                    <%=Html.ActionLink(
                            customerInfo.FullName
                            , ((string)ViewData["ActionNameForSelectedCustomer"])
                            , JoinParameters(customerInfo.id, (RouteValueDictionary) ViewData["AdditionalSelectionParameters"])
                            , null)%>
                
                
                    <%=customerInfo.LegalGuardianName %>
                
                
                    <%=customerInfo.HomePhone %>
                
                
                    <%=customerInfo.CellPhone %>
                
            
            <%}%>

这种方式对我来说非常难看,因为我讨厌在View部分中使用内联代码.

我的问题是 - 有什么更好的方法可以混合从动作传递的参数(在ViewData,TempData,其他...中)和构建动作链接时视图中的参数.

可能是我可以用其他方式建立这个链接？

谢谢!

编写扩展方法以将源字典合并到目标中.

public static class Util
{
    public static RouteValueDictionary Extend(this RouteValueDictionary dest, IEnumerable> src)
    {
        src.ToList().ForEach(x => { dest[x.Key] = x.Value; });
        return dest;
    }

    public static RouteValueDictionary Merge(this RouteValueDictionary source, IEnumerable> newData)
    {
        return (new RouteValueDictionary(source)).Extend(newData);
    }
}

用法:

Url.Action(actionName, controllerName, destRvd.Extend(srcRvd));

如果你想要一个包含两个内容的第三个字典 - 使用Merge.但这效率较低.如果您需要合并超过2个字典,此方法可以或多或少地有效地链接合并:

Url.Action(actionName, controllerName, destRvd.Extend(srcRvd1).Extend(srcRvd2));

有效地将3个词典合并为一个新词典:

Url.Action(actionName, controllerName, srcRvd1.Merge(srcRvd2).Extend(srcRvd3));

是 - 您可以RouteValueDictionary使用Union方法将两个(或更多)对象合并在一起.微软在这里有很好的Union方法示例代码,但微软在使用RouteValueDictionary Unions方面并不是很清楚(因此我的帖子的原因).

鉴于以下课程......

public class Student
{
    public int StudentID { get; set; }
    public string FirstName { get; set; }
    public string LastNamse { get; set; }
    public string Email { get; set; }
    public DateTime DateOfBirth { get; set; }
}

public class Address
{
    public string StreetLine1 { get; set; }
    public string StreetLine2 { get; set; }
    public string Suburb { get; set; }
    public string State { get; set; }
    public string PostCode { get; set; }
}

......以及一些示例代码......

Student aStudent = new Student();
aStudent.StudentID = 1234;
aStudent.FirstName = "Peter";
aStudent.LastNamse = "Wilson";
aStudent.Email = "peterwilson_69@example.com";
aStudent.DateOfBirth = new DateTime(1969, 12, 31);

Address homeAddr = new Address();
homeAddr.StreetLine1 = "Unit 99, Floor 10";
homeAddr.StreetLine2 = "99-199 Example Street";
homeAddr.Suburb = "Sydney";
homeAddr.State = "NSW";
homeAddr.PostCode = "2001";

初始化并向对象添加KeyValue元素RouteValueDictionary:

RouteValueDictionary routeStudent = new RouteValueDictionary(aStudent);
RouteValueDictionary routeAddress = new RouteValueDictionary(homeAddr);

...使用Union运算符合并两个字典对象:

RouteValueDictionary routeCombined = new RouteValueDictionary(routeStudent.Union(routeAddress).ToDictionary(k => k.Key, k => k.Value));

您现在可以将routeCombined变量传递给适当的方法(例如ActionLink).

@Html.ActionLink("Click to pass routeValues to the RouteAPI", "MyActionName", routeCombined);

写出调试窗口......

foreach (KeyValuePair n in routeCombined)
    System.Diagnostics.Debug.WriteLine(n.Key + ": " + n.Value);

......将产生以下内容:

StudentID: 1234
FirstName: Peter
LastNamse: Wilson
Email: peterwilson_69@example.com
DateOfBirth: 31/12/1969 12:00:00 AM
StreetLine1: Unit 99, Floor 10
StreetLine2: 99-199 Example Street
Suburb: Sydney
State: NSW
PostCode: 2001