使用SMTP从Python发送邮件

我正在使用以下方法使用SMTP从Python发送邮件.这是正确的使用方法还是我遗失了？

from smtplib import SMTP
import datetime

debuglevel = 0

smtp = SMTP()
smtp.set_debuglevel(debuglevel)
smtp.connect('YOUR.MAIL.SERVER', 26)
smtp.login('USERNAME@DOMAIN', 'PASSWORD')

from_addr = "John Doe "
to_addr = "foo@bar.com"

subj = "hello"
date = datetime.datetime.now().strftime( "%d/%m/%Y %H:%M" )

message_text = "Hello\nThis is a mail from your server\n\nBye\n"

msg = "From: %s\nTo: %s\nSubject: %s\nDate: %s\n\n%s" 
        % ( from_addr, to_addr, subj, date, message_text )

smtp.sendmail(from_addr, to_addr, msg)
smtp.quit()

Vincent Marc.. 107

我使用的脚本非常相似; 我在这里发布它作为如何使用电子邮件.*模块生成MIME消息的示例; 因此可以轻松修改此脚本以附加图片等.

我依靠我的ISP添加日期时间标题.

我的ISP要求我使用安全的smtp连接来发送邮件,我依靠smtplib模块(可从http://www1.cs.columbia.edu/~db2501/ssmtplib.py下载)

与在脚本中一样,用于在SMTP服务器上进行身份验证的用户名和密码(下面给出的虚拟值)在源中以纯文本形式显示.这是一个安全漏洞; 但最好的选择取决于你需要多少小心(想要？)来保护这些.

=======================================

#! /usr/local/bin/python


SMTPserver = 'smtp.att.yahoo.com'
sender =     'me@my_email_domain.net'
destination = ['recipient@her_email_domain.com']

USERNAME = "USER_NAME_FOR_INTERNET_SERVICE_PROVIDER"
PASSWORD = "PASSWORD_INTERNET_SERVICE_PROVIDER"

# typical values for text_subtype are plain, html, xml
text_subtype = 'plain'


content="""\
Test message
"""

subject="Sent from Python"

import sys
import os
import re

from smtplib import SMTP_SSL as SMTP       # this invokes the secure SMTP protocol (port 465, uses SSL)
# from smtplib import SMTP                  # use this for standard SMTP protocol   (port 25, no encryption)

# old version
# from email.MIMEText import MIMEText
from email.mime.text import MIMEText

try:
    msg = MIMEText(content, text_subtype)
    msg['Subject']=       subject
    msg['From']   = sender # some SMTP servers will do this automatically, not all

    conn = SMTP(SMTPserver)
    conn.set_debuglevel(False)
    conn.login(USERNAME, PASSWORD)
    try:
        conn.sendmail(sender, destination, msg.as_string())
    finally:
        conn.quit()

except:
    sys.exit( "mail failed; %s" % "CUSTOM_ERROR" ) # give an error message

添加`msg ['To'] =','.join(destination)`,否则在gmail中不会查看目的地 (9认同)

将`from ssmtplib import SMTP_SSL替换为SMTP`,用`from smtplib import SMTP_SSL as SMTP`,这个例子可以在标准Python库中使用. (2认同)

---

madman2890.. 83

我常用的方法......差别不大但有点不同

import smtplib
from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText

msg = MIMEMultipart()
msg['From'] = 'me@gmail.com'
msg['To'] = 'you@gmail.com'
msg['Subject'] = 'simple email in python'
message = 'here is the email'
msg.attach(MIMEText(message))

mailserver = smtplib.SMTP('smtp.gmail.com',587)
# identify ourselves to smtp gmail client
mailserver.ehlo()
# secure our email with tls encryption
mailserver.starttls()
# re-identify ourselves as an encrypted connection
mailserver.ehlo()
mailserver.login('me@gmail.com', 'mypassword')

mailserver.sendmail('me@gmail.com','you@gmail.com',msg.as_string())

mailserver.quit()

而已

1> Vincent Marc..：

---

我使用的脚本非常相似; 我在这里发布它作为如何使用电子邮件.*模块生成MIME消息的示例; 因此可以轻松修改此脚本以附加图片等.

我依靠我的ISP添加日期时间标题.

我的ISP要求我使用安全的smtp连接来发送邮件,我依靠smtplib模块(可从http://www1.cs.columbia.edu/~db2501/ssmtplib.py下载)

与在脚本中一样,用于在SMTP服务器上进行身份验证的用户名和密码(下面给出的虚拟值)在源中以纯文本形式显示.这是一个安全漏洞; 但最好的选择取决于你需要多少小心(想要？)来保护这些.

=======================================

#! /usr/local/bin/python


SMTPserver = 'smtp.att.yahoo.com'
sender =     'me@my_email_domain.net'
destination = ['recipient@her_email_domain.com']

USERNAME = "USER_NAME_FOR_INTERNET_SERVICE_PROVIDER"
PASSWORD = "PASSWORD_INTERNET_SERVICE_PROVIDER"

# typical values for text_subtype are plain, html, xml
text_subtype = 'plain'


content="""\
Test message
"""

subject="Sent from Python"

import sys
import os
import re

from smtplib import SMTP_SSL as SMTP       # this invokes the secure SMTP protocol (port 465, uses SSL)
# from smtplib import SMTP                  # use this for standard SMTP protocol   (port 25, no encryption)

# old version
# from email.MIMEText import MIMEText
from email.mime.text import MIMEText

try:
    msg = MIMEText(content, text_subtype)
    msg['Subject']=       subject
    msg['From']   = sender # some SMTP servers will do this automatically, not all

    conn = SMTP(SMTPserver)
    conn.set_debuglevel(False)
    conn.login(USERNAME, PASSWORD)
    try:
        conn.sendmail(sender, destination, msg.as_string())
    finally:
        conn.quit()

except:
    sys.exit( "mail failed; %s" % "CUSTOM_ERROR" ) # give an error message

---

添加`msg ['To'] =','.join(destination)`,否则在gmail中不会查看目的地

---

将`from ssmtplib import SMTP_SSL替换为SMTP`,用`from smtplib import SMTP_SSL as SMTP`,这个例子可以在标准Python库中使用.

2> madman2890..：

---

我常用的方法......差别不大但有点不同

import smtplib
from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText

msg = MIMEMultipart()
msg['From'] = 'me@gmail.com'
msg['To'] = 'you@gmail.com'
msg['Subject'] = 'simple email in python'
message = 'here is the email'
msg.attach(MIMEText(message))

mailserver = smtplib.SMTP('smtp.gmail.com',587)
# identify ourselves to smtp gmail client
mailserver.ehlo()
# secure our email with tls encryption
mailserver.starttls()
# re-identify ourselves as an encrypted connection
mailserver.ehlo()
mailserver.login('me@gmail.com', 'mypassword')

mailserver.sendmail('me@gmail.com','you@gmail.com',msg.as_string())

mailserver.quit()

而已

---

IMO,这是这个帖子中最好的答案.

---

对于python3，使用：`from email.mime.multipart import MIMEMultipart from email.mime.text import MIMEText`

---

我同意,这是最好的答案,应该被接受.实际接受的那个是劣等的.

3> 小智..：

---

此外,如果您想使用TLS而不是SSL执行smtp auth,那么您只需更改端口(使用587)并执行smtp.starttls().这对我有用:

...
smtp.connect('YOUR.MAIL.SERVER', 587)
smtp.ehlo()
smtp.starttls()
smtp.ehlo()
smtp.login('USERNAME@DOMAIN', 'PASSWORD')
...

4> pjz..：

---

我看到的主要问题是你没有处理任何错误:.login()和.sendmail()都记录了他们可以抛出的异常,似乎.connect()必须有一些方法来表明它是无法连接 - 可能是底层套接字代码抛出的异常.

5> Satish..：

---

那这个呢？

import smtplib

SERVER = "localhost"

FROM = "sender@example.com"
TO = ["user@example.com"] # must be a list

SUBJECT = "Hello!"

TEXT = "This message was sent with Python's smtplib."

# Prepare actual message

message = """\
From: %s
To: %s
Subject: %s

%s
""" % (FROM, ", ".join(TO), SUBJECT, TEXT)

# Send the mail

server = smtplib.SMTP(SERVER)
server.sendmail(FROM, TO, message)
server.quit()

6> Mark Ransom..：

---

确保没有任何阻止SMTP的防火墙.我第一次尝试发送电子邮件时,它被Windows防火墙和迈克菲阻止 - 永远都找到了它们.

7> Abdul Majeed..：

---

以下代码对我来说很好:

import smtplib

to = 'mkyong2002@yahoo.com'
gmail_user = 'mkyong2002@gmail.com'
gmail_pwd = 'yourpassword'
smtpserver = smtplib.SMTP("smtp.gmail.com",587)
smtpserver.ehlo()
smtpserver.starttls()
smtpserver.ehlo() # extra characters to permit edit
smtpserver.login(gmail_user, gmail_pwd)
header = 'To:' + to + '\n' + 'From: ' + gmail_user + '\n' + 'Subject:testing \n'
print header
msg = header + '\n this is test msg from mkyong.com \n\n'
smtpserver.sendmail(gmail_user, to, msg)
print 'done!'
smtpserver.quit()

参考:http://www.mkyong.com/python/how-do-send-email-in-python-via-smtplib/