使用linq查询xmlnode

您的XML结构很不幸,因为它在层次结构的三个级别使用Product元素.你有其他类似于"家庭"的元素吗？

假设我们只想要家用产品,您可以使用:

计算每个便宜/昂贵的项目

xe.Element("Product") // Select the Product desc="household" element
  .Elements() // Select the elements below it
  .Select(element => new { Name=(string) element.Attribute("desc"),
                           Count=element.Elements().Count() });

列出所有类别

xe.Descendants() // Select all descendant elements
  .Attributes() // All attributes from all elements
  // Limit it to "category" elements
  .Where(attr => attr.Name == "category")
  // Select the value
  .Select(attr => attr.Value)
  // Remove duplicates
  .Distinct();

要对此进行排序,请.OrderBy(x => x)在最后使用.

选择"昂贵"的产品

xe.Descendants() // Select all elements
  // Only consider those with a "Costly" description
  .Where(element => (string) element.Attribute("desc") == "Costly")
  // Select the subelements of that element, and flatten the result
  .SelectMany(element => element.Elements());

好吧,我个人觉得它更容易XmlDocument:

    XmlDocument root = new XmlDocument();
    root.LoadXml(xml); // or .Load(path);

    var categories = root.SelectNodes(
        "/root/Product/Product/Product/@category")
        .Cast().Select(cat => cat.InnerText).Distinct();
    var sortedCategories = categories.OrderBy(cat => cat);
    foreach (var category in sortedCategories)
    {
        Console.WriteLine(category);
    }

    var totalItems = root.SelectNodes(
         "/root/Products/Product/Product").Count;
    Console.WriteLine(totalItems);

    foreach (XmlElement prod in root.SelectNodes(
        "/root/Product/Product[@desc='Costly']/Product"))
    {
        Console.WriteLine(prod.GetAttribute("desc"));
    }