数字中最频繁的数字

目标是计算出一个长数字中最常见的数字.例如,213523432455555555将返回5.

print('Question 4')



def most_frequent(number):
    analysisnumber=map(int,str(number))
    returnvalue=[0,0,0,0,0,0,0,0,0,0]
highest = 0
total2=0
for i in range(0,len(str(number))):
    returnvalue[analysisnumber[i]] = list(map(i,analysisnumber))
for i in range(0,20):
    if i < 10:
        if returnvalue[i] > highest:
            highest = returnvalue[i]
    if i > 10:
        if returnvalue[i-10] == highest:
            total2+=highest
print("The most frequent number",end="")
if total2 > highest:
    print("s are: ")
    for i in range(0,10):
        if returnvalue[i] == highest:
            print(i)
else:
    print(" is ", end="")
    for i in range(0,10):
        if returnvalue[i] == highest:
            print(i)
            break
number=int(input("Enter the number intended for analysis:"))
most_frequent(number)

我明白了

TypeError: 'int' object is not callable

错误.会爱一些帮助!

这样做,使用Counter:

>>> from collections import Counter
>>> i = 24325872039847324509823475
>>> c = Counter(str(i))
>>> c
Counter({'2': 5, '3': 4, '4': 4, '5': 3, '7': 3, '8': 3, '0': 2, '9': 2})
>>> max(c.items(), key= lambda (x,y): y)
('2', 5)

或者只是使用(感谢@tobias_k):

>>> c.most_common(1)
[('2', 5)]

你正在使用错误的地图功能.

returnvalue[analysisnumber[i]] = list(map(i,analysisnumber))

映射的第一个值(来自文档)是函数): map(function, iterable, ...)

你提供了一个int(i).