Swift 2 - 合并两个数组

我想合并两个数组:

数组1 [["aaa","111"],["bbb","222"],["ccc","333"]]

阵列2 [["ddd","444"],["eee","555"],["fff","666"]]

我想要实现的是拥有一个具有尊重数组位置的值的单个数组,例如:

合并数组 [["aaa","111"],["ddd","444"],["bbb","222"],["eee","555"],["ccc","333"],["fff","666"]]

我怎么能用Swift 2做到这一点

let arr1 = [["aaa","111"],["bbb","222"],["ccc","333"]]
let arr2 = [["ddd","444"],["eee","555"],["fff","666"]]
let arr3 = arr1 + arr2
print(arr3) // [["aaa", "111"], ["bbb", "222"], ["ccc", "333"], ["ddd", "444"], ["eee", "555"], ["fff", "666"]]

在你的情况下,有特定的要求

let arr4 = zip(arr1, arr2).reduce([]) { (var arr, p:(Array, Array)) -> [[String]] in
    arr.append(p.0)
    arr.append(p.1)
    return arr
}
print(arr4) // [["aaa", "111"], ["ddd", "444"], ["bbb", "222"], ["eee", "555"], ["ccc", "333"], ["fff", "666"]]

根据您在笔记中提到的需求进行更新,您可以通过这种方式添加其余值(请先将arr4更改为var arr4 !!!)

var i = arr4.count / 2
while i < arr1.count {
    arr4.append(arr1[i++])
}

while i < arr2.count {
    arr4.append(arr2[i++])
}
print(arr4)

这给了你

[["aaa", "111"], ["ddd", "444"], ["bbb", "222"], ["eee", "555"], ["ccc", "333"], ["fff", "666"], ["zzz", "755"]]

它应该工作,即使其中一个数组是空的