UITableViewRowAction带有图标和文字

有几个类似的问题,但我认为应该有使用Swift3的iOS 10的最新答案,它不使用私有API,并且不依赖于您将图标限制为unicode表情符号.

我现在有三个动作的表行:

func tableView(_ tableView: UITableView, editActionsForRowAt indexPath: IndexPath) -> [UITableViewRowAction]? {
    let rename = UITableViewRowAction(style: .normal, title: "Rename") { (_, indexPath) in
        self.renameEntry(indexPath)
    }
    let locate = UITableViewRowAction(style: .normal, title: "Locate") { (_, indexPath) in
        self.locateEntry(indexPath)
    }
    locate.backgroundEffect = UIVisualEffect()
    let delete = UITableViewRowAction(style: .default, title: "Forget") { (_, indexPath) in
        self.deleteEntry(indexPath)
    }
    return [delete, locate, rename]
}

但是,我想要的不是我所选择的大小和样式的居中文字的颜色方块,而是:

我尝试使用backgroundColor,但只是将图像平铺在按钮上,并没有改变文本的位置或颜色.所以它必须不仅仅是

theAction.backgroundColor = UIColor(patternImage: UIImage(named: "renameImage")!) 

有这样做的好方法吗？

我最终做的是在飞行中生成一个图像作为背景.这需要使用黑客/聪明技巧或两个.

第一部分是标准委托方法:

func tableView(_ tableView: UITableView, editActionsForRowAt indexPath: IndexPath) -> [UITableViewRowAction]? {

    let stockWidth = String(repeating: " ", count: 8)
    let rename = UITableViewRowAction(style: .normal, title: stockWidth) { (_, indexPath) in
        self.renameEntry(indexPath)
    }
    self.fixAction(rename, text: "Rename", image: UIImage(named: "pencilEdit")!, color: UIColor(52, 61, 70))
    let locate = UITableViewRowAction(style: .normal, title: stockWidth) { (_, indexPath) in
        self.locateEntry(indexPath)
    }
    self.fixAction(locate, text: "Locate", image: UIImage(named: "locatePin")!, color: UIColor(38, 107, 215))
    let delete = UITableViewRowAction(style: .normal, title: stockWidth) { (_, indexPath) in
        self.deleteEntry(indexPath)
    }
    self.fixAction(delete, text: "Forget", image: UIImage(named: "triggerDeleteSelector")!, color: UIColor(227, 34, 60))
    let gap = UITableViewRowAction(style: .normal, title: "") { (_, _) in
        // pass
    }
    gap.backgroundColor = UIColor.clear
    return [gap, delete, locate, rename]
}

那里有两个不明显的细节.首先,动作从传入的文本字符串中获取其宽度.如果您没有通过一些不可见的空格字符给它一些宽度,则背景图像将不会有任何区域被绘制.这就是为什么stockWidth前3个动作中使用的字符串.它的8个字符宽度由fixAction生成背景图像的方法共享.

第二个细节是在底部包含第四个"间隙"动作.出于某种原因,如果第一个动作具有作为平铺图案的背景颜色,则它将在其他动作下向左伸展.我发现我必须在前面插入这个零宽度没有操作以避免这种情况.

func fixAction(_ action:UITableViewRowAction, text:String, image:UIImage, color:UIColor) {
    // make sure the image is a mask that we can color with the passed color
    let mask = image.withRenderingMode(.alwaysTemplate) 
    // compute the anticipated width of that non empty string
    let stockSize = action.title!.sizeWithAttributes([NSFontAttributeName: UIFont.systemFont(ofSize: 18)])
    // I know my row height
    let height:CGFloat = 70
    // Standard action width computation seems to add 15px on either side of the text
    let width = (stockSize.width + 30).ceiling 
    let actionSize = CGSize(width: width, height: height)
    // lets draw an image of actionSize
    UIGraphicsBeginImageContextWithOptions(actionSize, false, 0.0)
    if let context = UIGraphicsGetCurrentContext() {
        context.clear(CGRect(origin: .zero, size: actionSize))
    }
    color.set()
    let attributes = [NSForegroundColorAttributeName: color, NSFontAttributeName: UIFont(name: "Avenir-Book", size: 13)]
    let textSize = text.size(attributes: attributes)
    // implementation of `half` extension left up to the student
    let textPoint = CGPoint(x: (width - textSize.width).half, y: (height - (textSize.height * 3)).half + (textSize.height * 2))
    text.draw(at: textPoint, withAttributes: attributes)
    let  maskHeight = textSize.height * 2
    let maskRect = CGRect(x: (width - maskHeight).half, y: textPoint.y - maskHeight, width: maskHeight, height: maskHeight)
    mask.draw(in: maskRect)
    if let result = UIGraphicsGetImageFromCurrentImageContext() {
        // adjust the passed in action's backgroundColor to a patternImage
        action.backgroundColor = UIColor(patternImage: result)
    }
    else {
        "WTH!!!".logError()
    }
    UIGraphicsEndImageContext()
}