为什么这两个字符串不相等？

我最近在考虑GUID,这让我尝试了这段代码:

Guid guid = Guid.NewGuid();
Console.WriteLine(guid.ToString()); //prints 6d1dc8c8-cd83-45b2-915f-c759134b93aa
Console.WriteLine(BitConverter.ToString(guid.ToByteArray())); //prints C8-C8-1D-6D-83-CD-B2-45-91-5F-C7-59-13-4B-93-AA
bool same=guid.ToString()==BitConverter.ToString(guid.ToByteArray()); //false
Console.WriteLine(same);

您可以看到所有字节都在那里,但是当我使用它们时,其中一半是错误的顺序BitConverter.ToString.为什么是这样？

根据Microsoft 文档:

请注意,返回的字节数组中的字节顺序与Guid值的字符串表示形式不同.开始的四字节组和接下来的两个双字节组的顺序相反,而最后两个字节组和结束六字节组的顺序相同.该示例提供了说明.

using System;

public class Example
{
   public static void Main()
   {
      Guid guid = Guid.NewGuid();
      Console.WriteLine("Guid: {0}", guid);
      Byte[] bytes = guid.ToByteArray();
      foreach (var byt in bytes)
         Console.Write("{0:X2} ", byt);

      Console.WriteLine();
      Guid guid2 = new Guid(bytes);
      Console.WriteLine("Guid: {0} (Same as First Guid: {1})", guid2, guid2.Equals(guid));
   }
}
// The example displays the following output:
//    Guid: 35918bc9-196d-40ea-9779-889d79b753f0
//    C9 8B 91 35 6D 19 EA 40 97 79 88 9D 79 B7 53 F0
//    Guid: 35918bc9-196d-40ea-9779-889d79b753f0 (Same as First Guid: True)