有没有办法计算2个字符串之间的%匹配?
我有一种情况,如果有85%,需要计算2个字符串之间的匹配
匹配然后我将结合2个表,我已经编写了组合2个表的代码
我的示例字符串是:
var str1 = 'i love javascript'; var str2 = 'i love javascripttt'; var matchPer = match(str1,str2); // result might be 80% , 85%, 90% ,95% etc
Ala Eddine J.. 9
像这样的东西?
var str1 = 'i love javascript';
var str2 = 'i love javascripttt';
function match(str1, str2){
var tmpValue = 0;
var minLength = str1.length;
if(str1.length > str2.length){
var minLength = str2.length;
}
var maxLength = str1.length;
if(str1.length < str2.length){
var maxLength = str2.length;
}
for(var i = 0; i < minLength; i++) {
if(str1[i] == str2[i]) {
tmpValue++;
}
}
var weight = tmpValue / maxLength;
return (weight * 100) + "%";
}
var matchPer = match(str1,str2);
console.log(matchPer); //outputs: 89.47%
console.log( match("aaaaa", "aaaaa") ); //outputs: 100%
console.log( match("aaaaa", "aXaaa") ); //outputs: 80%
console.log( match("aaaaa", "aXXaa") ); //outputs: 60%
console.log( match("aaaaa", "aXXXa") ); //outputs: 40%
console.log( match("aaaaa", "aXXXX") ); //outputs: 20%
像这样的东西?
var str1 = 'i love javascript';
var str2 = 'i love javascripttt';
function match(str1, str2){
var tmpValue = 0;
var minLength = str1.length;
if(str1.length > str2.length){
var minLength = str2.length;
}
var maxLength = str1.length;
if(str1.length < str2.length){
var maxLength = str2.length;
}
for(var i = 0; i < minLength; i++) {
if(str1[i] == str2[i]) {
tmpValue++;
}
}
var weight = tmpValue / maxLength;
return (weight * 100) + "%";
}
var matchPer = match(str1,str2);
console.log(matchPer); //outputs: 89.47%
console.log( match("aaaaa", "aaaaa") ); //outputs: 100%
console.log( match("aaaaa", "aXaaa") ); //outputs: 80%
console.log( match("aaaaa", "aXXaa") ); //outputs: 60%
console.log( match("aaaaa", "aXXXa") ); //outputs: 40%
console.log( match("aaaaa", "aXXXX") ); //outputs: 20%