有没有办法在PIL中指定矩形的宽度？

PIL rectangle不支持这个width论点.

这是一个绘制第一个初始矩形的方法,然后是向内的其他矩形 - 注意,线宽不沿边框居中.

def draw_rectangle(draw, coordinates, color, width=1):
    for i in range(width):
        rect_start = (coordinates[0][0] - i, coordinates[0][1] - i)
        rect_end = (coordinates[1][0] + i, coordinates[1][1] + i)
        draw.rectangle((rect_start, rect_end), outline = color)

# example usage

im = Image.open(image_path)
drawing = ImageDraw.Draw(im)

top_left = (50, 50)
bottom_right = (100, 100)

outline_width = 10
outline_color = "black"

draw_rectangle(drawing, (top_left, bottom_right), color=outline_color, width=outline_width)

除了四条线之外，您还可以绘制一条包含四个点的线，从而形成一个矩形：

def drawrect(drawcontext, xy, outline=None, width=0):
    (x1, y1), (x2, y2) = xy
    points = (x1, y1), (x2, y1), (x2, y2), (x1, y2), (x1, y1)
    drawcontext.line(points, fill=outline, width=width)

# example
from PIL import Image, ImageDraw
im = Image.new("RGB", (150, 150), color="white")
draw = ImageDraw.Draw(im)

drawrect(draw, [(50, 50), (100, 100)], outline="red", width=5)

im.show()