在.NET中有效地重定向标准输出

我试图从.NET程序调用php-cgi.exe.我使用RedirectStandardOutput将输出作为流返回,但整个过程非常慢.

你对我如何能加快速度有任何想法吗？还有其他技术吗？

    Dim oCGI As ProcessStartInfo = New ProcessStartInfo()
    oCGI.WorkingDirectory = "C:\Program Files\Application\php"
    oCGI.FileName = "php-cgi.exe"
    oCGI.RedirectStandardOutput = True
    oCGI.RedirectStandardInput = True
    oCGI.UseShellExecute = False
    oCGI.CreateNoWindow = True

    Dim oProcess As Process = New Process()

    oProcess.StartInfo = oCGI
    oProcess.Start()

    oProcess.StandardOutput.ReadToEnd()

Jader Dias.. 17

我发现的最佳解决方案是:

private void Redirect(StreamReader input, TextBox output)
{
    new Thread(a =>
    {
        var buffer = new char[1];
        while (input.Read(buffer, 0, 1) > 0)
        {
            output.Dispatcher.Invoke(new Action(delegate
            {
                output.Text += new string(buffer);
            }));
        };
    }).Start();
}

private void Window_Loaded(object sender, RoutedEventArgs e)
{
    process = new Process
    {
        StartInfo = new ProcessStartInfo
        {
            CreateNoWindow = true,
            FileName = "php-cgi.exe",
            RedirectStandardOutput = true,
            UseShellExecute = false,
            WorkingDirectory = @"C:\Program Files\Application\php",
        }
    };
    if (process.Start())
    {
        Redirect(process.StandardOutput, textBox1);
    }
}

这实际上是我见过的重定向输出的最佳解决方案......谢谢Jader! (2认同)

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Bob King.. 8

您可以使用OutputDataReceived事件接收数据,因为它被泵送到StdOut.

1> Jader Dias..：

---

我发现的最佳解决方案是:

private void Redirect(StreamReader input, TextBox output)
{
    new Thread(a =>
    {
        var buffer = new char[1];
        while (input.Read(buffer, 0, 1) > 0)
        {
            output.Dispatcher.Invoke(new Action(delegate
            {
                output.Text += new string(buffer);
            }));
        };
    }).Start();
}

private void Window_Loaded(object sender, RoutedEventArgs e)
{
    process = new Process
    {
        StartInfo = new ProcessStartInfo
        {
            CreateNoWindow = true,
            FileName = "php-cgi.exe",
            RedirectStandardOutput = true,
            UseShellExecute = false,
            WorkingDirectory = @"C:\Program Files\Application\php",
        }
    };
    if (process.Start())
    {
        Redirect(process.StandardOutput, textBox1);
    }
}

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这实际上是我见过的重定向输出的最佳解决方案......谢谢Jader!

2> Bob King..：

---

您可以使用OutputDataReceived事件接收数据,因为它被泵送到StdOut.

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@Vincent @Bob King此事件的问题在于它仅在输出收到换行符时被调用.我的解决方案在此线程中的另一个答案也适用于输出没有回车符或换行符.