在Darwin/OSX中以编程方式确定流程信息

我有一个具有以下成员函数的类:

/// caller pid
virtual pid_t Pid() const = 0; 

/// physical memory size in KB
virtual uint64_t Size() const = 0;  

/// resident memory for this process
virtual uint64_t Rss() const = 0; 

/// cpu used by this process
virtual double PercentCpu() const = 0; 

/// memory used by this process
virtual double PercentMemory() const = 0; 

/// number of threads in this process
virtual int32_t Lwps() const = 0; 

这个类的职责是返回有关调用者的进程信息.物理内存大小可以通过sysctl调用轻松确定,而pid是微不足道的,但除了在ps或top上调用popen并解析输出之外,其余的调用都没有找到 - 这是不可接受的.任何帮助将不胜感激.

要求:
在g ++ 4.0上编译
没有obj-c
OSX 10.5

流程信息来自pidinfo:

cristi:~ diciu$ grep proc_pidinfo /usr/include/libproc.h

int proc_pidinfo(int pid, int flavor, uint64_t arg,  void *buffer, int buffersize);

cpu负载来自host_statistics:

cristi:~ diciu$ grep -r host_statistics /usr/include/

/usr/include/mach/host_info.h:/* host_statistics() */

/usr/include/mach/mach_host.defs:routine host_statistics(

/usr/include/mach/mach_host.h:/* Routine host_statistics */

/usr/include/mach/mach_host.h:kern_return_t host_statistics

有关更多详细信息,请查看源代码,top并且lsof它们是开源的(您需要注册为Apple开发人员,但这是免费的):

https://opensource.apple.com/source/top/top-111.20.1/libtop.c.auto.html

稍后编辑:所有这些接口都是特定于版本的,因此在编写生产代码(libproc.h)时需要考虑到这一点:

/*
 * This header file contains private interfaces to obtain process information.
 * These interfaces are subject to change in future releases.
 */

既然你说没有Objective-C我们将排除大多数MacOS框架.

您可以使用getrusage()获得CPU时间,这可以为您的进程收取用户和系统CPU时间总量.要获得CPU百分比,您需要每秒对getrusage值进行一次快照(或者您想要的粒度).

#include 

struct rusage r_usage;

if (getrusage(RUSAGE_SELF, &r_usage)) {
    /* ... error handling ... */
}

printf("Total User CPU = %ld.%ld\n",
        r_usage.ru_utime.tv_sec,
        r_usage.ru_utime.tv_usec);
printf("Total System CPU = %ld.%ld\n",
        r_usage.ru_stime.tv_sec,
        r_usage.ru_stime.tv_usec);

getrusage结构中有一个RSS字段,但在MacOS X 10.5中似乎总是为零.Michael Knight几年前写了一篇关于如何确定RSS的博客文章.