在Internet Explorer中相当于Firebug的"复制XPath"？

我有一个仅限Internet Explorer的Web应用程序.

我正在探索如何自动化测试.

Selenium看起来是一个很好的工具,但是为了能够激活链接等,我需要告诉它它们在哪里.该应用程序并未构建此类测试,因此id关键元素通常没有属性.

没问题,我想,我可以使用XPath表达式.但是,如果通过检查页面的来源来完成,那么找一个正确的XPath,例如一个按钮,就是一种巨大的痛苦.

使用Firefox/Firebug,我可以选择元素,然后使用"Copy XPath"来获取表达式.

我有IE开发人员工具栏,它令人沮丧地接近.我可以单击以选择感兴趣的元素并显示有关它的各种信息.但我看不出任何方便的方法来确定它的XPath.

那么有没有办法用IE做到这一点？

我会使用bookmarklets.我有一个XPath相关,但我不知道它是否适用于IE.我得去,但我会测试它,并给它,如果它适用于IE浏览器.

我的书签为Web开发人员提供了两个bookmarklet站点:Subsimple的bookmarklet和Squarefree的Bookmarklets.那里有很多有用的东西......

[编辑]好的,我回来了.我的小书签仅用于FF,并不是最佳的.我终于改写了它,尽管使用了原始的想法.找不到我发现的地方.

扩展JS:

function getNode(node)
{
  var nodeExpr = node.tagName;
  if (nodeExpr == null)  // Eg. node = #text
    return null;
  if (node.id != '')
  {
    nodeExpr += "[@id='" + node.id + "']";
    // We don't really need to go back up to //HTML, since IDs are supposed
    // to be unique, so they are a good starting point.
    return "/" + nodeExpr;
  }
// We don't really need this
//~   if (node.className != '')
//~   {
//~     nodeExpr += "[@class='" + node.className + "']";
//~   }
  // Find rank of node among its type in the parent
  var rank = 1;
  var ps = node.previousSibling;
  while (ps != null)
  {
    if (ps.tagName == node.tagName)
    {
      rank++;
    }
    ps = ps.previousSibling;
  }
  if (rank > 1)
  {
    nodeExpr += '[' + rank + ']';
  }
  else
  {
    // First node of its kind at this level. Are there any others?
    var ns = node.nextSibling;
    while (ns != null)
    {
      if (ns.tagName == node.tagName)
      {
        // Yes, mark it as being the first one
        nodeExpr += '[1]';
        break;
      }
      ns = ns.nextSibling;
    }
  }
  return nodeExpr;
}

var currentNode;
// Standard (?)
if (window.getSelection != undefined) 
  currentNode = window.getSelection().anchorNode;
// IE (if no selection, that's BODY)
else 
  currentNode = document.selection.createRange().parentElement();
if (currentNode == null)
{
  alert("No selection");
  return;
}
var path = [];
// Walk up the Dom
while (currentNode != undefined)
{
  var pe = getNode(currentNode);
  if (pe != null)
  {
    path.push(pe);
    if (pe.indexOf('@id') != -1)
      break;  // Found an ID, no need to go upper, absolute path is OK
  }
  currentNode = currentNode.parentNode;
}
var xpath = "/" + path.reverse().join('/');
alert(xpath);
// Copy to clipboard
// IE
if (window.clipboardData) clipboardData.setData("Text", xpath);
// FF's code to handle clipboard is much more complex 
// and might need to change prefs to allow changing the clipboard content.
// I omit it here as it isn't part of the original request.

您必须选择元素并激活书签以获取其XPath.

现在,书签版本(感谢Bookmarklet Builder):

IE
(我不得不分两部分,因为IE不喜欢很长的书签(最大尺寸因IE版本而异!).你必须激活第一个(功能def)然后第二个.用IE6测试.)

javascript:function getNode(node){var nodeExpr=node.tagName;if(!nodeExpr)return null;if(node.id!=''){nodeExpr+="[@id='"+node.id+"']";return "/"+nodeExpr;}var rank=1;var ps=node.previousSibling;while(ps){if(ps.tagName==node.tagName){rank++;}ps=ps.previousSibling;}if(rank>1){nodeExpr+='['+rank+']';}else{var ns=node.nextSibling;while(ns){if(ns.tagName==node.tagName){nodeExpr+='[1]';break;}ns=ns.nextSibling;}}return nodeExpr;}
javascript:function o__o(){var currentNode=document.selection.createRange().parentElement();var path=[];while(currentNode){var pe=getNode(currentNode);if(pe){path.push(pe);if(pe.indexOf('@id')!=-1)break;}currentNode=currentNode.parentNode;}var xpath="/"+path.reverse().join('/');clipboardData.setData("Text", xpath);}o__o();

FF

javascript:function o__o(){function getNode(node){var nodeExpr=node.tagName;if(nodeExpr==null)return null;if(node.id!=''){nodeExpr+="[@id='"+node.id+"']";return "/"+nodeExpr;}var rank=1;var ps=node.previousSibling;while(ps!=null){if(ps.tagName==node.tagName){rank++;}ps=ps.previousSibling;}if(rank>1){nodeExpr+='['+rank+']';}else{var ns=node.nextSibling;while(ns!=null){if(ns.tagName==node.tagName){nodeExpr+='[1]';break;}ns=ns.nextSibling;}}return nodeExpr;}var currentNode=window.getSelection().anchorNode;if(currentNode==null){alert("No selection");return;}var path=[];while(currentNode!=undefined){var pe=getNode(currentNode);if(pe!=null){path.push(pe);if(pe.indexOf('@id')!=-1)break;}currentNode=currentNode.parentNode;}var xpath="/"+path.reverse().join('/');alert(xpath);}o__o();