在Python中,是否可以阻塞if-elif-else块？

电影票:电影院根据一个人的年龄收取不同的票价.如果一个人未满3岁,则该机票是免费的; 如果他们在3到12之间,门票是10美元; 如果他们超过12岁,门票是15美元.写一个循环,在其中询问用户他们的年龄,然后告诉他们他们的电影票的成本.

我希望这个程序具有戒烟价值.我可以使用0作为我的退出值,但我想使用'退出'.

prompt = "What is your age? "
prompt += "\nEnter 'quit' to close program."

age = 0

while True:


     age = raw_input(prompt)
        if age == 'quit':
            break
        else:
            age = int(age)
            if age < 3:
                print("The movie ticket is FREE for you.")
            elif 3 <= age < 12:
                print("The movie ticket is $10 for you.")
            elif age >= 12:
                print("The movie ticker is $15 for you.")

Dan D... 6

我想指出你不需要这个else条款.您可以在前一个缩进级别包含其余条件,因为break退出循环而不是继续循环体的其余部分.

而不是

    if age == 'quit':
        break
    else:
        age = int(age)

只是:

    if age == 'quit':
        break

    age = int(age)

如果不清楚这里是整个程序的变化:

prompt = "What is your age? "
prompt += "\nEnter 'quit' to close program."

while True:

    age = raw_input(prompt)
    if age == 'quit':
        break

    age = int(age)
    if age < 3:
        print("The movie ticket is FREE for you.")
    elif 3 <= age < 12:
        print("The movie ticket is $10 for you.")
    elif age >= 12:
        print("The movie ticker is $15 for you.")

我还删除了无用的赋值:age = 0因为该值age = raw_input(prompt)在被读取之前被替换.

我想指出你不需要这个else条款.您可以在前一个缩进级别包含其余条件,因为break退出循环而不是继续循环体的其余部分.

而不是

    if age == 'quit':
        break
    else:
        age = int(age)

只是:

    if age == 'quit':
        break

    age = int(age)

如果不清楚这里是整个程序的变化:

prompt = "What is your age? "
prompt += "\nEnter 'quit' to close program."

while True:

    age = raw_input(prompt)
    if age == 'quit':
        break

    age = int(age)
    if age < 3:
        print("The movie ticket is FREE for you.")
    elif 3 <= age < 12:
        print("The movie ticket is $10 for you.")
    elif age >= 12:
        print("The movie ticker is $15 for you.")

我还删除了无用的赋值:age = 0因为该值age = raw_input(prompt)在被读取之前被替换.