foreach/for循环消除边界检查的特殊情况是什么？还有哪些界限检查呢？
标准
for(int i = 0; i < array.Length; i++) {
...
}
循环是一个允许JIT以安全地取出数组的边界检查(索引是否是内[0..length-1])
所述foreach过阵列环等同于标准for超过阵列循环.
编辑: 罗伯特杰普森指出:
如果阵列是本地的,这将被优化.如果数组是从其他地方访问,边界检查仍将进行.参考: JIT,NGen和其他托管代码生成的东西> CLR中的数组边界检查消除 ">阵列边界检查CLR中的消除
谢谢!不知道自己.
SealedSun是对的.不要优化你在C++中的方式.JIT非常聪明,可以为您做正确的事.您始终可以用不同的方式对循环进行编码,然后检查IL代码.
static void Main(string[] args)
{
int[] array = new int[100];
00000000 push edi
00000001 push esi
00000002 push eax
00000003 xor eax,eax
00000005 mov dword ptr [esp],eax
00000008 mov edx,64h
0000000d mov ecx,79174292h
00000012 call 49E73198
00000017 mov esi,eax
int sum = 0;
00000019 xor edx,edx
0000001b mov dword ptr [esp],edx
for(int index = 0; index < array.Length; index++)
0000001e mov edi,dword ptr [esi+4]
00000021 test edi,edi
00000023 jle 00000033
{
sum += array[index];
00000025 mov eax,dword ptr [esi+edx*4+8]
00000029 add dword ptr [esp],eax
for(int index = 0; index < array.Length; index++)
0000002c add edx,1
0000002f cmp edi,edx
00000031 jg 00000025
}
Console.WriteLine(sum.ToString());
00000033 mov esi,dword ptr [esp]
00000036 call 493765F8
0000003b push eax
0000003c mov ecx,esi
0000003e xor edx,edx
00000040 call 49E83A8B
00000045 mov edi,eax
00000047 mov edx,88h
0000004c mov ecx,1
00000051 call 49E731B0
00000056 mov esi,eax
00000058 cmp dword ptr [esi+70h],0
0000005c jne 00000068
0000005e mov ecx,1
00000063 call 4936344C
00000068 mov ecx,dword ptr [esi+70h]
0000006b mov edx,edi
0000006d mov eax,dword ptr [ecx]
0000006f call dword ptr [eax+000000D8h]
00000075 pop ecx
}
00000076 pop esi
00000077 pop edi
00000078 ret
现在,如果以C++的方式优化代码,您将获得以下内容:
static void Main(string[] args)
{
int[] array = new int[100];
00000000 push edi
00000001 push esi
00000002 push ebx
00000003 push eax
00000004 xor eax,eax
00000006 mov dword ptr [esp],eax
00000009 mov edx,64h
0000000e mov ecx,79174292h
00000013 call 49E73198
00000018 mov esi,eax
int sum = 0;
0000001a xor edx,edx
0000001c mov dword ptr [esp],edx
int length = array.Length;
0000001f mov ebx,dword ptr [esi+4]
for (int index = 0; index < length; index++)
00000022 test ebx,ebx
00000024 jle 0000003B
00000026 mov edi,dword ptr [esi+4]
{
sum += array[index];
00000029 cmp edx,edi <-- HERE
0000002b jae 00000082 <-- HERE
0000002d mov eax,dword ptr [esi+edx*4+8]
00000031 add dword ptr [esp],eax
for (int index = 0; index < length; index++)
00000034 add edx,1
00000037 cmp edx,ebx
00000039 jl 00000029
}
Console.WriteLine(sum.ToString());
0000003b mov esi,dword ptr [esp]
0000003e call 493765F8
00000043 push eax
00000044 mov ecx,esi
00000046 xor edx,edx
00000048 call 49E83A8B
0000004d mov edi,eax
0000004f mov edx,88h
00000054 mov ecx,1
00000059 call 49E731B0
0000005e mov esi,eax
00000060 cmp dword ptr [esi+70h],0
00000064 jne 00000070
00000066 mov ecx,1
0000006b call 4936344C
00000070 mov ecx,dword ptr [esi+70h]
00000073 mov edx,edi
00000075 mov eax,dword ptr [ecx]
00000077 call dword ptr [eax+000000D8h]
0000007d pop ecx
}
0000007e pop ebx
0000007f pop esi
00000080 pop edi
00000081 ret
00000082 call 4A12746B
00000087 int 3
顺便说一下 - 这与foreach声明是一样的:
static void Main(string[] args)
{
int[] array = new int[100];
00000000 push edi
00000001 push esi
00000002 push eax
00000003 xor eax,eax
00000005 mov dword ptr [esp],eax
00000008 mov edx,64h
0000000d mov ecx,79174292h
00000012 call 49E73198
00000017 mov esi,eax
int sum = 0;
00000019 xor edx,edx
0000001b mov dword ptr [esp],edx
for(int index = 0; index < array.Length; index++)
0000001e mov edi,dword ptr [esi+4]
00000021 test edi,edi
00000023 jle 00000033
{
sum += array[index];
00000025 mov eax,dword ptr [esi+edx*4+8]
00000029 add dword ptr [esp],eax
for(int index = 0; index < array.Length; index++)
0000002c add edx,1
0000002f cmp edi,edx
00000031 jg 00000025
}
Console.WriteLine(sum.ToString());
00000033 mov esi,dword ptr [esp]
00000036 call 493765F8
0000003b push eax
0000003c mov ecx,esi
0000003e xor edx,edx
00000040 call 49E83A8B
00000045 mov edi,eax
00000047 mov edx,88h
0000004c mov ecx,1
00000051 call 49E731B0
00000056 mov esi,eax
00000058 cmp dword ptr [esi+70h],0
0000005c jne 00000068
0000005e mov ecx,1
00000063 call 4936344C
00000068 mov ecx,dword ptr [esi+70h]
0000006b mov edx,edi
0000006d mov eax,dword ptr [ecx]
0000006f call dword ptr [eax+000000D8h]
00000075 pop ecx
}
00000076 pop esi
00000077 pop edi
00000078 ret
不要在没有数字的情况下尝试优化代码.正如您所看到的那样,如果您不采取行动,JIT将为您做很多事情.在优化之前使用分析器.总是.
有关详细信息,请参见
http://codebetter.com/blogs/david.hayden/archive/2005/02/27/56104.aspx
基本上,如果你有一个for循环,并且你明确地引用了IList.Count或Array.Length,JIT将捕获它,并跳过边界检查.它比预先计算列表长度更快.
我相信,在列表或数组上的foreach将在内部执行相同的操作.
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