jQuery - 附加变量时,只增加1个选择

然而,'myoption'仅附加到1选择而不是另一个.

问题:如何在不声明相同变量的情况下将其附加到两者？

干杯!

这是预期的行为,您需要创建.clone()对象并将append()其创建为第二个元素.

$.each(selectValues, function(key, value) {
    var myoption = $("")
        .attr("value", value.ownerid)
        .text(value.name);

    $('#select1').append(myoption);

    //Append cloned object      
    $('#select2').append(myoption.clone());
});

var selectValues = [{ "ownerid": " ", "name": " "}, {  "ownerid": 123,  "name":"Tom"}, {  "ownerid": 345,  "name": "Dick"}, {  "ownerid": 888,  "name": "Harry"}];

$.each(selectValues, function(key, value) {
  var myoption = $("")
    .attr("value", value.ownerid)
    .text(value.name);

  $('#select1').append(myoption);
  $('#select2').append(myoption.clone());
});

Select 1

Select 2