Java通过经纬度坐标获取两个点之间的直线距离的示例

import java.math.BigDecimal;
import java.util.HashMap;
import java.util.Map;
 
public class DistanceUtil {
 
  // 椭球的长半轴
  private static double EARTH_RADIUS = 6378.137;
 
  /**
   * 计算弧度
   */
  private static double rad(double d) {
    return d * Math.PI / 180.0;
  }
 
  /**
   * 通过经纬度计算AB两点间的距离
   * A点经度:longitude1、A点纬度:latitude1、 
   * B点经度:longitude2、 B点纬度:latitude2
   */
  public static Map getDistance(double longitude1, double latitude1, double longitude2, double latitude2) {
    double radLat1 = rad(latitude1);
    double radLat2 = rad(latitude2);
    double a = radLat1 - radLat2;
    double b = rad(longitude1) - rad(longitude2);
    double distance = 2 * Math.asin(Math.sqrt(Math.pow(Math.sin(a / 2), 2) + Math.cos(radLat1) * Math.cos(radLat2) * Math.pow(Math.sin(b / 2), 2)));
    distance = distance * EARTH_RADIUS;
    Map map = new HashMap();
    BigDecimal decimal = new BigDecimal(distance);
    //结果保留2位小数
    distance = decimal.setScale(2, BigDecimal.ROUND_HALF_UP).doubleValue();
    map.put("units", "km");
    map.put("distance", distance);
    return map; // {distance=700.0, units=km}
  }
 
  public static void main(String[] args) {
   // A点 117.034727 36.665777 B点 117.041006 36.665871
    Map m = DistanceUtil.getDistance(36.665777, 117.034727, 36.665871, 117.041006);
    System.out.println(m);//AB直线700米左右
  } 
}

SET NAMES utf8mb4;
SET FOREIGN_KEY_CHECKS = 0;
 
-- ----------------------------
-- Table structure for lt_coordinates
-- ----------------------------
DROP TABLE IF EXISTS `user_coordinates`;
CREATE TABLE `user_coordinates` (
 `id` varchar(255) CHARACTER SET utf8mb4 COLLATE utf8mb4_unicode_ci NOT NULL,
 `user_id` varchar(32) CHARACTER SET utf8mb4 COLLATE utf8mb4_unicode_ci DEFAULT NULL COMMENT '用户id',
 `longitude` double(11, 8) DEFAULT NULL COMMENT '经度',
 `latitude` double(11, 8) DEFAULT NULL COMMENT '纬度',
 PRIMARY KEY (`id`) USING BTREE
) ENGINE = InnoDB CHARACTER SET = utf8mb4 COLLATE = utf8mb4_unicode_ci COMMENT = '用户经纬度坐标' ROW_FORMAT = Dynamic;
 
-- ----------------------------
-- Records of lt_coordinates
-- ----------------------------

INSERT INTO `user_coordinates` VALUES ('1', '1001', 117.12345678, 36.12345678);
SET FOREIGN_KEY_CHECKS = 1;
SELECT
  id,
  user_id,
  ROUND(6378.138*2*ASIN(SQRT(POW(SIN((纬度*PI()/180-latitude*PI()/180)/2),2)+COS(纬度*PI()/180)*COS(latitude*PI()/180)*POW(SIN((经度*PI()/180-longitude*PI()/180)/2),2)))) AS distance
FROM
  user_coordinates
HAVING
  distance <= '范围大小(千米)'
ORDER BY
  distance
ASC