javascript - 微信接入JS时遇到这个问题

Warning: fopen(access_token.json) [function.fopen]: failed to open stream: Permission denied in jssdk.php on line 79

Warning: fwrite() expects parameter 1 to be resource, boolean given in jssdk.php on line 80

Warning: fclose() expects parameter 1 to be resource, boolean given in jssdk.php on line 81

Warning: fopen(jsapi_ticket.json) [function.fopen]: failed to open stream: Permission denied in jssdk.php on line 56

Warning: fwrite() expects parameter 1 to be resource, boolean given in jssdk.php on line 57

Warning: fclose() expects parameter 1 to be resource, boolean given in jssdk.php on line 58

回复内容：

Warning: fopen(access_token.json) [function.fopen]: failed to open stream: Permission denied in jssdk.php on line 79

Warning: fwrite() expects parameter 1 to be resource, boolean given in jssdk.php on line 80

Warning: fclose() expects parameter 1 to be resource, boolean given in jssdk.php on line 81

Warning: fopen(jsapi_ticket.json) [function.fopen]: failed to open stream: Permission denied in jssdk.php on line 56

Warning: fwrite() expects parameter 1 to be resource, boolean given in jssdk.php on line 57

Warning: fclose() expects parameter 1 to be resource, boolean given in jssdk.php on line 58

是什么环境下。如果是Linux环境就把，就把access_token.json和jsapi_ticket.json的读写权限打开。

别告诉我你用的是SAE。 SAE不支持本地写权限，得修改代码。
你可以把access token存储到SAE的memcache里面

如果是其他的系统，请把写权限打开。

这个是在SAE作为测试环境的原因, 今天刚好我也遇到了. SAE是没有文件的读写权限的.
节哀