按两个元素对嵌套列表进行排序

假设我有一个如下列表:

[['Harry', '4'], ['Anthony', '10'], ['Adam', '7'], ['Joe', '6'], ['Ben', '10']]
# we can say the first element in it's lists is `name`, the second is `score`

我想把它分类:

[['Anthony', '10'], ['Ben', '10'], ['Adam', '7'], ['Joe', '6'], ['Harry', '4']]

因此,首先按分数降序对其进行排序,然后按名称按升序对其进行排序.

我试过了:

>>> sorted(l, key=lambda x: (int(x[1]), x[0]))
[['Harry', '4'], ['Joe', '6'], ['Adam', '7'], ['Anthony', '10'], ['Ben', '10']]

它正在工作,所以现在我只需要逆转它:

>>> sorted(l, key=lambda x: (int(x[1]), x[0]), reverse=True)
[['Ben', '10'], ['Anthony', '10'], ['Adam', '7'], ['Joe', '6'], ['Harry', '4']]

啊,reverse=True简单地颠倒了列表但没有给出期望输出.所以我只想反转输出int(x[1]),但不是x[0].

我怎样才能做到这一点？

>>> sorted(l, key=lambda x: (-int(x[1]), x[0]))
[['Anthony', '10'], ['Ben', '10'], ['Adam', '7'], ['Joe', '6'], ['Harry', '4']]

基本上,通过更改键的得分部分的符号,排序键将是:

(-10, 'Anthony'),
(-10, 'Ben'),
(-7, 'Adam'),
(-6, 'Joe'),
(-4, 'Harry')

因此,(a, b) < (c, d) <=> (a < c) or (a == c and b < d)您最终得到了所需的排序顺序.