Ansible:当"不"满足"when"条件时,如何避免注册变量？

我有以下Ansible Playbook代码:

- name: Users | Generate password for user (Debian/Ubuntu)
  shell: makepasswd --chars=20
  register: make_password
  when: ansible_distribution in ['Debian', 'Ubuntu']

- name: Users | Generate password for user (Fedora)
  shell: makepasswd -m 20 -M 20
  register: make_password
  when: ansible_distribution in ['Fedora', 'Amazon']

- name: Users | Generate password for user (CentOS)
  shell: mkpasswd -l 20
  register: make_password
  when: ansible_distribution in ['CentOS']

- name: debug
  debug: var=make_password

哪个输出:

TASK: [users | debug] 
ok: [127.0.0.1] => {
                     "var": {
                       "make_password": {
                         "changed": false,
                         "skipped": true
                       }
                     }
                   }

...因为register无论when条件如何,每个块都会被执行.

我如何解决这个问题,以免make_password在when条件不满足时被覆盖？

或者如果这是你可以看到的我想要完成的错误方法,请告诉我一个更好的方法.

不幸的是,这是预期的行为.来自Ansible变量

注意 如果任务失败或被跳过,变量仍然会注册失败或跳过状态,避免注册变量的唯一方法是使用标记.

我不知道如何使用标签来解决您的问题.

编辑:我找到了一种方法,虽然原油解决方案.存储结果,以便不会覆盖它

  - set_fact: mypwd="{{make_password}}"
    when: make_password.changed

所以你的代码看起来像:

- name: Users | Generate password for user (Debian/Ubuntu)
  shell: makepasswd --chars=20
  register: make_password
  when: ansible_distribution in ['Debian', 'Ubuntu']

- set_fact: mypwd="{{make_password}}"
  when: make_password.changed

- name: Users | Generate password for user (Fedora)
  shell: makepasswd -m 20 -M 20
  register: make_password
  when: ansible_distribution in ['Fedora', 'Amazon']

- set_fact: mypwd="{{make_password}}"
  when: make_password.changed

- name: Users | Generate password for user (CentOS)
  shell: mkpasswd -l 20
  register: make_password
  when: ansible_distribution in ['CentOS']

- set_fact: mypwd="{{make_password}}"
  when: make_password.changed

- name: debug
  debug: var=mypwd