C ++ OpenCV 2.4.11：列出所有摄像机

我想使用C ++，OpenCV 2.4.11，Windows 8.1和Qt Creator 3.4.2列出所有连接的网络摄像头（USB网络摄像头和内部网络摄像头）。对我而言，通过以下方式获取可访问的网络摄像头数量就足够了：

VideoCapture videoCapture(0); // Will access my internal laptop webcam.
VideoCapture videoCapture(1); // Will access the first connected usb webcam.

这是我的代码：

// Following procedure detects, how many webcams are accessible from 0 on upwards.
numberOfDevices = 0;
bool noError = true;

while (noError)
{
    try
    {
        // Check if camera is available.
        VideoCapture videoCapture(numberOfDevices); // Will crash if not available, hence try/catch.

        // ...
    }
    catch (...)
    {
        noError = false;
    }

    // If above call worked, we have found another camera.
    numberOfDevices++;
}

如果我激活了内部网络摄像头，则尝试块中的代码将起作用。当我在硬件管理器中停用内置摄像机（并且笔记本电脑未连接其他摄像机）时，调用失败，并显示以下错误消息（调试模式）：

Exception Triggered
---------------------------
The inferior stopped because it triggered an exception.
Stopped in thread 0 by: 
Exception at 0x7ff8533d9090, code: 0xc0000005: read access violation at: 0x0, flags=0x0 (first chance).

和以下两个构建问题：

Exception at 0x7ff871af8b9c, code: 0xa1a01db1: , flags=0x0 (first chance)

Exception at 0x7ff8533d9090, code: 0xc0000005: read access violation at: 0x0, flags=0x0 (first chance)

如何获取发生的错误？如您所见，try / catch不起作用。

还是有一种方法可以使我在OpenCV中访问所有可用的网络摄像头而又不会出现这种麻烦的循环？