我一直在尝试的代码和出了什么问题:http://ideone.com/cvLRLg
using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication1 { public class Minion { public static int manaCost; public static int attack; public static int health; public static string cardText; public Minion(int mana, int atk, int h, string txt) { manaCost = mana; attack = atk; health = h; cardText = txt; } public void displayStats(string name) { Console.WriteLine(name + "\nMana Cost: " + manaCost + "\nAttack: " + attack + "\nHealth: " + health + "\n" + cardText + "\n"); } } class Program { static void Main(string[] args) { ListindexList = new List (); Dictionary minionList = new Dictionary (); //buffer so I start at 1 and not 0 indexList.Add("MissingNo"); //make a Wolfrider card indexList.Add("Wolfrider"); Minion Wolfrider = new Minion(3, 3, 1, "Charge"); minionList.Add(indexList[1], Wolfrider); //make a Goldshire Footman card indexList.Add("Goldshire Footman"); Minion GoldshireFootman = new Minion(1, 1, 2, "Taunt"); minionList.Add(indexList[2], GoldshireFootman); //look through all my cards for (int i = 1; i < indexList.Count(); i++) minionList[indexList[i]].displayStats(indexList[i]); Console.ReadLine(); } } }
我一直在努力教自己C#,但这一直困扰着我.我想创建一个接受字符串的Dictionary然后返回一个Minion(新类).
Minion在制作时会接受四个参数,因此我必须专门用一行代码来制作一个新的Minion,然后将其添加到Dictionary中.
然而,当我经历我拥有的所有Minions时,由于某种原因,第一个让我回到OTHER Minion的属性.
Wolfrider Mana Cost: 1 Attack: 1 Health: 2 Taunt Goldshire Footman Mana Cost: 1 Attack: 1 Health: 2 Taunt
列表工作正常,因为名称是正确的......但Wolfrider具有Goldshire Footman的属性.
有没有更有效/优化的方法来做到这一点?如果没有,我做错了什么?
主要问题是您的成员是static
:
public static int manaCost
所以基本上,你影响的最后一个值获胜.将它们转换为实例属性:
public int ManaCost { get; set; }
然后摆脱indexList
并直接使用你的Minion的名字作为字典键.