调用跨线程事件的最简洁方法

我发现.NET事件模型是这样的,我经常会在一个线程上引发事件并在另一个线程上侦听它.我想知道将后台线程中的事件编组到我的UI线程的最简洁方法是什么.

根据社区建议,我用过这个:

// earlier in the code
mCoolObject.CoolEvent+= 
           new CoolObjectEventHandler(mCoolObject_CoolEvent);
// then
private void mCoolObject_CoolEvent(object sender, CoolObjectEventArgs args)
{
    if (InvokeRequired)
    {
        CoolObjectEventHandler cb =
            new CoolObjectEventHandler(
                mCoolObject_CoolEvent);
        Invoke(cb, new object[] { sender, args });
        return;
    }
    // do the dirty work of my method here
}

Domenic.. 43

我在网上有一些代码.它比其他建议好得多; 绝对检查一下.

样品用法:

private void mCoolObject_CoolEvent(object sender, CoolObjectEventArgs args)
{
    // You could use "() =>" in place of "delegate"; it's a style choice.
    this.Invoke(delegate
    {
        // Do the dirty work of my method here.
    });
}

Shaun Austin.. 27

几点意见:

不要在类似的代码中显式创建简单的委托,除非你是pre-2.0,所以你可以使用:

   BeginInvoke(new EventHandler(mCoolObject_CoolEvent), 
               sender, 
               args);

private void mCoolObject_CoolEvent(object sender, CoolObjectEventArgs args)
{
    if (InvokeRequired)
    {
        Invoke(new Action(mCoolObject_CoolEvent), sender, args);
        return;
    }
    // do the dirty work of my method here
}

private void mCoolObject_CoolEvent(object sender, CoolObjectEventArgs args)
{
    // You could use "() =>" in place of "delegate"; it's a style choice.
    this.Invoke(delegate
    {
        // Do the dirty work of my method here.
    });
}

   BeginInvoke(new EventHandler(mCoolObject_CoolEvent), 
               sender, 
               args);

private void mCoolObject_CoolEvent(object sender, CoolObjectEventArgs args)
{
    if (InvokeRequired)
    {
        Invoke(new Action(mCoolObject_CoolEvent), sender, args);
        return;
    }
    // do the dirty work of my method here
}