PHP:如何从API调用解析JSON？

我有一个CURL响应,如下所示:

{"page_number":2,"items":[],"items_per_page":1,"kind":"search#companies","total_results":0,"start_index":1} 

我所需要的只是价值 "total_results":0

所以我"total_results"想这样:

$url = "https://api.companieshouse.gov.uk/search/companies?q=POOdfgdfgyygfhfgfgfghgfP&items_per_page=1&start_index=0";

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_USERPWD, "my_password");
curl_setopt($ch, CURLOPT_HTTPAUTH, CURLAUTH_BASIC);

$output = curl_exec($ch);
$retcode = curl_getinfo($ch, CURLINFO_HTTP_CODE);
$info = curl_getinfo($ch);
curl_close($ch);

echo $output->total_results[0];

然而,当我$output->total_results[0];回应时,我的页面上没有任何回应.所以我真的不知道我做错了什么!

有人可以就这个问题提出建议吗？

任何帮助,将不胜感激.

你得到的回应是JSON字符串.您可以stdClass使用json_decode将其解析为对象:

$object = json_decode( $output );

然后,您可以访问所需的字段:

$total_results = $object->total_results;

或者,您可以将JSON字符串解析为数组:

$array = json_decode( $output, true );

得到var:

$total_results = $array['total_results'];