从浏览器运行以下脚本后,我发现它将数据插入我的MySQL数据库两次.我只在我的代码中打了一个电话,一切似乎都井然有序.我在想这可能与在if语句中调用查询有关,但是我无法找到与此相关的任何内容.
我正在使用以下查询运行脚本:
http://businesstools.vmem.int/performance/api/start.php?device=7300&config=thin
当我SELECT
在此表上运行语句时,它返回以下内容.星号放在我运行的查询旁边,未标记的行作为辅助插入进入.
mysql> SELECT * FROM test; +-----+-----+-----+---------------------+ | tid | cid | did | runtime | +-----+-----+-----+---------------------+ | *1 | 1 | 5 | 2015-12-22 15:54:56 | | 2 | 1 | 5 | 2015-12-22 15:55:29 | | *3 | 1 | 5 | 2015-12-22 15:57:52 | | 4 | 1 | 5 | 2015-12-22 15:57:57 | | *5 | 0 | 5 | 2015-12-22 15:57:59 | | 6 | 0 | 5 | 2015-12-22 16:06:28 | | *7 | 0 | 5 | 2015-12-22 16:06:31 | | *8 | 1 | 5 | 2015-12-22 16:06:35 | | *9 | 1 | 5 | 2015-12-22 16:06:38 | | *10 | 1 | 5 | 2015-12-22 16:06:41 | | *11 | 1 | 6 | 2015-12-22 16:06:49 | | *12 | 1 | 5 | 2015-12-22 16:10:21 | +-----+-----+-----+---------------------+ 12 rows in set (0.00 sec)
PHP
mysql_connect("localhost", xxxx, xxxx); mysql_select_db(performanceData); mysql_set_charset("utf8"); //Assert provided device configuration exists $deviceSwitch = false; $deviceNum; $configSwitch = false; $configNum; $errorSwitch = false; $returnArray = array("testID"=>-1, "error"=>"NULL"); $errorString = "ERROR"; $deviceInfo = mysql_query("SELECT d.did AS 'did', d.name AS 'name', c.cid AS 'cid', c.lunType AS 'lunType' FROM device d JOIN config c ON d.did = c.did;"); while ($row = mysql_fetch_assoc($deviceInfo)) { if (strcmp($_GET["device"], $row["name"]) == 0) { $deviceSwitch = true; $deviceNum = $row["did"]; if (strcmp($_GET["config"], $row["lunType"]) == 0) { $configSwitch = true; $configNum = $row["cid"]; } } } if ($deviceSwitch && $configSwitch) { if (mysql_query("INSERT INTO test (cid, did) VALUES (".$configNum.", ".$deviceNum.");")) { $returnArray["testID"] = mysql_insert_id(); } else { $errorString .= " - Failed to insert into database, please contact sysadmin"; $errorSwitch = true; } } else { $errorSwitch = true; $errorString .= " - Improper device or config formatting"; } if ($errorSwitch) $returnArray["error"] = $errorString; echo json_encode($returnArray); ?>
MySQL表设置
CREATE TABLE test( tid int NOT NULL AUTO_INCREMENT, cid int NOT NULL, did int NOT NULL, runtime TIMESTAMP DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY (tid), FOREIGN KEY (cid) REFERENCES config (cid) ON DELETE CASCADE, FOREIGN KEY (did) REFERENCES device (did) ON DELETE CASCADE );
编辑:进一步测试后,我发现这只是一个问题,直到我的数据库自动递增ID达到7,然后它才能正常运行.
编辑2:这似乎是由浏览器预取引起的,这是因为我使用相同的URL足够时间让浏览器将其记录在"访问量最大的页面"中.打开新选项卡时,它会预取URL,将不需要的行添加到数据库中.暴露了直接数据库GET Web API的一个关键弱点.
编辑3:我决定强制CLI交互来解决这个问题.这消除了该问题,但不允许基于URL/GET的脚本访问.