如何获取列表列表中的每个元素？

我正在为我的作业制作心脏游戏,但我不知道如何在列表列表中获取每个元素:

>>>Cards = [[["QS","5H","AS"],["2H","8H"],["7C"]],[["9H","5C],["JH"]],[["7D"]]]

而我想到的是:

for values in cards:
    for value in values:

但我想我的元素有2个列表.如何计算卡中有3个和1个列表的那个？

像这样:

>>> Cards = [[["QS","5H","AS"],["2H","8H"],["7C"]],[["9H","5C"],["JH"]],["7D"]]
>>> from compiler.ast import flatten
>>> flatten(Cards) 
['QS', '5H', 'AS', '2H', '8H', '7C', '9H', '5C', 'JH', '7D']

正如nacholibre指出的那样,该compiler软件包已被弃用.这是以下来源flatten:

def flatten(seq):
    l = []
    for elt in seq:
        t = type(elt)
        if t is tuple or t is list:
            for elt2 in flatten(elt):
                l.append(elt2)
        else:
            l.append(elt)
    return l

略显模糊的oneliner:

>>> [a for c in Cards for b in c for a in b]
['QS', '5H', 'AS', '2H', '8H', '7C', '9H', '5C', 'JH', '7', 'D']

您可能想要给出a,b和c更具描述性的名称.