当有人动摇iPhone时,我想做出反应.我并不特别在乎它们是如何摇晃它的,只是它在一瞬间大力挥手.有谁知道怎么检测到这个？
在3.0中,现在有一种更简单的方法 - 挂钩新的运动事件.
主要技巧是你需要有一些UIView(不是UIViewController),你想要firstResponder来接收震动事件消息.以下是您可以在任何UIView中使用以获取震动事件的代码:
@implementation ShakingView
- (void)motionEnded:(UIEventSubtype)motion withEvent:(UIEvent *)event
{
if ( event.subtype == UIEventSubtypeMotionShake )
{
// Put in code here to handle shake
}
if ( [super respondsToSelector:@selector(motionEnded:withEvent:)] )
[super motionEnded:motion withEvent:event];
}
- (BOOL)canBecomeFirstResponder
{ return YES; }
@end
您可以轻松地将任何UIView(甚至系统视图)转换为只需通过仅使用这些方法对视图进行子类化(然后在IB中选择此新类型而不是基本类型,或在分配时使用它)来获取抖动事件的视图视图).
在视图控制器中,您要将此视图设置为第一响应者:
- (void) viewWillAppear:(BOOL)animated
{
[shakeView becomeFirstResponder];
[super viewWillAppear:animated];
}
- (void) viewWillDisappear:(BOOL)animated
{
[shakeView resignFirstResponder];
[super viewWillDisappear:animated];
}
不要忘记,如果您有其他视图从用户操作(如搜索栏或文本输入字段)成为第一响应者,您还需要在另一个视图辞职时恢复摇动视图第一响应者状态!
即使将applicationSupportsShakeToEdit设置为NO,此方法也有效.
从我的Diceshaker应用程序:
// Ensures the shake is strong enough on at least two axes before declaring it a shake.
// "Strong enough" means "greater than a client-supplied threshold" in G's.
static BOOL L0AccelerationIsShaking(UIAcceleration* last, UIAcceleration* current, double threshold) {
double
deltaX = fabs(last.x - current.x),
deltaY = fabs(last.y - current.y),
deltaZ = fabs(last.z - current.z);
return
(deltaX > threshold && deltaY > threshold) ||
(deltaX > threshold && deltaZ > threshold) ||
(deltaY > threshold && deltaZ > threshold);
}
@interface L0AppDelegate : NSObject {
BOOL histeresisExcited;
UIAcceleration* lastAcceleration;
}
@property(retain) UIAcceleration* lastAcceleration;
@end
@implementation L0AppDelegate
- (void)applicationDidFinishLaunching:(UIApplication *)application {
[UIAccelerometer sharedAccelerometer].delegate = self;
}
- (void) accelerometer:(UIAccelerometer *)accelerometer didAccelerate:(UIAcceleration *)acceleration {
if (self.lastAcceleration) {
if (!histeresisExcited && L0AccelerationIsShaking(self.lastAcceleration, acceleration, 0.7)) {
histeresisExcited = YES;
/* SHAKE DETECTED. DO HERE WHAT YOU WANT. */
} else if (histeresisExcited && !L0AccelerationIsShaking(self.lastAcceleration, acceleration, 0.2)) {
histeresisExcited = NO;
}
}
self.lastAcceleration = acceleration;
}
// and proper @synthesize and -dealloc boilerplate code
@end
该组合可防止震动事件多次触发,直到用户停止摇动.
我终于使用了这个Undo/Redo Manager Tutorial中的代码示例.
这正是您需要做的:
在App的Delegate中设置applicationSupportsShakeToEdit属性:
- (void)applicationDidFinishLaunching:(UIApplication *)application {
application.applicationSupportsShakeToEdit = YES;
[window addSubview:viewController.view];
[window makeKeyAndVisible];
}
在视图控制器中添加/覆盖canBecomeFirstResponder,viewDidAppear:和viewWillDisappear:方法:
-(BOOL)canBecomeFirstResponder {
return YES;
}
-(void)viewDidAppear:(BOOL)animated {
[super viewDidAppear:animated];
[self becomeFirstResponder];
}
- (void)viewWillDisappear:(BOOL)animated {
[self resignFirstResponder];
[super viewWillDisappear:animated];
}
将motionEnded方法添加到View Controller:
- (void)motionEnded:(UIEventSubtype)motion withEvent:(UIEvent *)event
{
if (motion == UIEventSubtypeMotionShake)
{
// your code
}
}
首先,肯德尔7月10日的回答是正确的.
现在......我想做类似的事情(在iPhone OS 3.0+中),只是在我的情况下,我想在应用程序范围内,所以我可以在发生震动时提醒应用程序的各个部分.这就是我最终做的事情.
首先,我将UIWindow子类化.这很容易.创建一个带有界面的新类文件MotionWindow : UIWindow(随意选择自己的,natch).添加如下方法:
- (void)motionEnded:(UIEventSubtype)motion withEvent:(UIEvent *)event {
if (event.type == UIEventTypeMotion && event.subtype == UIEventSubtypeMotionShake) {
[[NSNotificationCenter defaultCenter] postNotificationName:@"DeviceShaken" object:self];
}
}
更改@"DeviceShaken"为您选择的通知名称.保存文件.
现在,如果您使用MainWindow.xib(库存Xcode模板的东西),请进入并将Window对象的类从UIWindow更改为MotionWindow或您调用它的任何内容.保存xib.如果以编程方式设置UIWindow,请在那里使用新的Window类.
现在您的应用程序正在使用专门的UIWindow类.无论您想要被告知摇晃,请注册他们的通知!像这样:
[[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(deviceShaken) name:@"DeviceShaken" object:nil];
要以观察者身份移除自己:
[[NSNotificationCenter defaultCenter] removeObserver:self];
我把它放在viewWillAppear:和viewWillDisappear:视图控制器所关注的地方.确保您对震动事件的响应知道它是否"已在进行中".否则,如果设备连续摇动两次,您将遇到交通拥堵.这样,您可以忽略其他通知,直到您真正完成对原始通知的响应.
另外:你可以选择提示关闭motionBegan和motionEnded.由你决定.就我而言,其效果总是需要发生后,该装置是在休息(对启动时震动),所以我用motionEnded.尝试两者,看看哪一个更有意义......或检测/通知两者!
还有一个(好奇的？)观察:请注意,此代码中没有第一响应者管理的迹象.到目前为止,我只尝试使用Table View控制器,所有内容似乎都能很好地协同工作!我不能担保其他情况.
肯德尔等.al - 任何人都可以说为什么UIWindow子类可能会如此？是因为窗户位于食物链的顶端吗？
我发现这篇文章寻找一个"摇晃"的实现.millenomi的答案对我来说效果很好,虽然我正在寻找一些需要更多"摇动动作"才能触发的东西.我用int shakeCount替换为布尔值.我还重新实现了Objective-C中的L0AccelerationIsShaking()方法.您可以通过调整添加到shakeCount的ammount来调整所需的抖动量.我不确定我是否已经找到了最佳值,但到目前为止似乎运行良好.希望这有助于某人:
- (void)accelerometer:(UIAccelerometer *)accelerometer didAccelerate:(UIAcceleration *)acceleration {
if (self.lastAcceleration) {
if ([self AccelerationIsShakingLast:self.lastAcceleration current:acceleration threshold:0.7] && shakeCount >= 9) {
//Shaking here, DO stuff.
shakeCount = 0;
} else if ([self AccelerationIsShakingLast:self.lastAcceleration current:acceleration threshold:0.7]) {
shakeCount = shakeCount + 5;
}else if (![self AccelerationIsShakingLast:self.lastAcceleration current:acceleration threshold:0.2]) {
if (shakeCount > 0) {
shakeCount--;
}
}
}
self.lastAcceleration = acceleration;
}
- (BOOL) AccelerationIsShakingLast:(UIAcceleration *)last current:(UIAcceleration *)current threshold:(double)threshold {
double
deltaX = fabs(last.x - current.x),
deltaY = fabs(last.y - current.y),
deltaZ = fabs(last.z - current.z);
return
(deltaX > threshold && deltaY > threshold) ||
(deltaX > threshold && deltaZ > threshold) ||
(deltaY > threshold && deltaZ > threshold);
}
PS:我已将更新间隔设置为1/15秒.
[[UIAccelerometer sharedAccelerometer] setUpdateInterval:(1.0 / 15)];
您需要通过加速度计检查加速度计:didAccelerate:方法,该方法是UIAccelerometerDelegate协议的一部分,并检查值是否超过抖动所需的移动量的阈值.
加速计中有一些不错的示例代码:didAccelerate:方法位于iPhone开发人员网站上可用的GLPaint示例中AppController.m的底部.
在iOS 8.3版本(可能更早)与雨燕,它作为压倒一切的简单motionBegan或motionEnded在您的视图控制器的方法:
class ViewController: UIViewController {
override func motionBegan(motion: UIEventSubtype, withEvent event: UIEvent) {
println("started shaking!")
}
override func motionEnded(motion: UIEventSubtype, withEvent event: UIEvent) {
println("ended shaking!")
}
}
这是您需要的基本代理代码:
#define kAccelerationThreshold 2.2
#pragma mark -
#pragma mark UIAccelerometerDelegate Methods
- (void)accelerometer:(UIAccelerometer *)accelerometer didAccelerate:(UIAcceleration *)acceleration
{
if (fabsf(acceleration.x) > kAccelerationThreshold || fabsf(acceleration.y) > kAccelerationThreshold || fabsf(acceleration.z) > kAccelerationThreshold)
[self myShakeMethodGoesHere];
}
还要在接口中设置相应的代码.即:
@interface MyViewController:UIViewController
查看GLPaint示例.
http://developer.apple.com/library/ios/#samplecode/GLPaint/Introduction/Intro.html
在ViewController.m文件中添加以下方法,它正常工作
-(BOOL) canBecomeFirstResponder
{
/* Here, We want our view (not viewcontroller) as first responder
to receive shake event message */
return YES;
}
-(void) motionEnded:(UIEventSubtype)motion withEvent:(UIEvent *)event
{
if(event.subtype==UIEventSubtypeMotionShake)
{
// Code at shake event
UIAlertView *alert=[[UIAlertView alloc] initWithTitle:@"Motion" message:@"Phone Vibrate"delegate:self cancelButtonTitle:@"OK" otherButtonTitles: nil];
[alert show];
[alert release];
[self.view setBackgroundColor:[UIColor redColor]];
}
}
- (void)viewDidAppear:(BOOL)animated
{
[super viewDidAppear:animated];
[self becomeFirstResponder]; // View as first responder
}
很抱歉发布这个作为答案而不是评论但是你可以看到我是Stack Overflow的新手,所以我还没有足够的信誉来发表评论!
无论如何,我第二次@cire关于确保在视图是视图层次结构的一部分后设置第一个响应者状态.因此,在视图控制器viewDidLoad方法中设置第一响应者状态将不起作用.如果你不确定它是否正常工作,则[view becomeFirstResponder]返回一个你可以测试的布尔值.
另一点:如果您不想不必要地创建UIView子类,则可以使用视图控制器捕获shake事件.我知道这不是那么麻烦,但仍有选择.只需将Kendall放入UIView子类的代码片段移动到控制器中,然后发送becomeFirstResponder和resignFirstResponder消息self而不是UIView子类.
首先,我知道这是一个旧帖子,但它仍然相关,我发现两个最高投票的答案并没有尽早发现.这是怎么做的:
在目标的构建阶段将CoreMotion链接到您的项目:
在您的ViewController中:
- (BOOL)canBecomeFirstResponder {
return YES;
}
- (void)motionBegan:(UIEventSubtype)motion withEvent:(UIEvent *)event
{
if (motion == UIEventSubtypeMotionShake) {
// Shake detected.
}
}
京公网安备 11010802040832号 | 京ICP备19059560号-6 