如何解开阵列？

我需要生成一个list对scipy.optimize.minimize的boundry condition,就应该是这样的:

bonds = [(0., 0.99),(-30, 30),(-30, 30),(0., 30),(0., 30),(-0.99, 0.99),
        (0., 0.99),(-30, 30),(-30, 30),(0., 30),(0., 30),(-0.99, 0.99),
        (0., 0.99),(-30, 30),(-30, 30),(0., 30),(0., 30),(-0.99, 0.99),]

我想知道是否有任何优雅的方式吗？

我试过了:

bonds = [[(0., 0.99),(-30, 30),(-30, 30),(0., 30),(0., 30),(-0.99, 0.99)] for i in range(3)]

但这会产生

[[(0.0, 0.99), (-30, 30), (-30, 30), (0.0, 30), (0.0, 30), (-0.99, 0.99)],
 [(0.0, 0.99), (-30, 30), (-30, 30), (0.0, 30), (0.0, 30), (-0.99, 0.99)],
 [(0.0, 0.99), (-30, 30), (-30, 30), (0.0, 30), (0.0, 30), (-0.99, 0.99)]]

如何将内部数组移除[]到unravel内部数组中？或者还有其他好办法吗？

你可以做:

bonds = [(0., 0.99),(-30, 30),(-30, 30),(0., 30),(0., 30),(-0.99, 0.99)] * 3