如何确定类型是否实现特定的通用接口类型

假设以下类型定义:

public interface IFoo : IBar {}
public class Foo : IFoo {}

当只有受损的类型可用时,如何确定类型是否Foo实现了通用接口IBar？

通过使用TcKs的答案,它也可以使用以下LINQ查询完成:

bool isBar = foo.GetType().GetInterfaces().Any(x =>
  x.IsGenericType &&
  x.GetGenericTypeDefinition() == typeof(IBar<>));

你必须通过继承树上去,找到树中的每个类的所有接口,并比较typeof(IBar<>)与调用的结果Type.GetGenericTypeDefinition ,如果该接口是通用的.当然,这有点痛苦.

有关更多信息和代码,请参阅此答案和这些答案.

public interface IFoo : IBar {}
public class Foo : IFoo {}

var implementedInterfaces = typeof( Foo ).GetInterfaces();
foreach( var interfaceType in implementedInterfaces ) {
    if ( false == interfaceType.IsGeneric ) { continue; }
    var genericType = interfaceType.GetGenericTypeDefinition();
    if ( genericType == typeof( IFoo<> ) ) {
        // do something !
        break;
    }
}

作为辅助方法的扩展

public static bool Implements(this Type type, I @interface) where I : class
{
    if(((@interface as Type)==null) || !(@interface as Type).IsInterface)
        throw new ArgumentException("Only interfaces can be 'implemented'.");

    return (@interface as Type).IsAssignableFrom(type);
}

var testObject = new Dictionary();
result = testObject.GetType().Implements(typeof(IDictionary)); // true!

public static bool Implements(this Type type) where TInterface : class {
    var interfaceType = typeof(TInterface);

    if (!interfaceType.IsInterface)
        throw new InvalidOperationException("Only interfaces can be implemented.");

    return (interfaceType.IsAssignableFrom(type));
}

    if (!featureType.Implements())
        throw new InvalidCastException();