场景:
用户有两个显示器.
他们的浏览器在辅助监视器上打开.
他们单击浏览器中的一个链接,该链接使用特定的顶部和左侧窗口偏移调用window.open().
弹出窗口始终在其主监视器上打开.
在JavaScript中是否有任何方法可以让弹出窗口在与初始浏览器窗口(开启者)相同的监视器上打开?
您无法指定监视器,但可以将弹出窗口的位置指定为相对于单击导致窗口弹出的位置.
使用getMouseXY()函数获取要作为window.open()方法的left和top args传递的值.(左侧和顶部的args仅适用于V3和更高版本的浏览器).
window.open docs:http: //www.javascripter.net/faq/openinga.htm
function getMouseXY( e ) { if ( event.clientX ) { // Grab the x-y pos.s if browser is IE. CurrentLeft = event.clientX + document.body.scrollLeft; CurrentTop = event.clientY + document.body.scrollTop; } else { // Grab the x-y pos.s if browser isn't IE. CurrentLeft = e.pageX; CurrentTop = e.pageY; } if ( CurrentLeft < 0 ) { CurrentLeft = 0; }; if ( CurrentTop < 0 ) { CurrentTop = 0; }; return true; }
这是我从Facebook oauth API无耻地逆向设计的东西.在Firefox/Chrome中的主显示器和辅助显示器上进行测试.
function popup_params(width, height) { var a = typeof window.screenX != 'undefined' ? window.screenX : window.screenLeft; var i = typeof window.screenY != 'undefined' ? window.screenY : window.screenTop; var g = typeof window.outerWidth!='undefined' ? window.outerWidth : document.documentElement.clientWidth; var f = typeof window.outerHeight != 'undefined' ? window.outerHeight: (document.documentElement.clientHeight - 22); var h = (a < 0) ? window.screen.width + a : a; var left = parseInt(h + ((g - width) / 2), 10); var top = parseInt(i + ((f-height) / 2.5), 10); return ',,left=' + left + ',top=' + top + ',scrollbars=1'; } window.open(url, "window name", "location=1,toolbar=0," + popup_params(modal_width, modal_height));
// Pops a window relative to the current window position function popup(url, winName, xOffset, yOffset) { var x = (window.screenX || window.screenLeft || 0) + (xOffset || 0); var y = (window.screenY || window.screenTop || 0) + (yOffset || 0); return window.open(url, winName, 'top=' +y+ ',left=' +x)) }
像下面这样调用它,它将在当前窗口的顶部打开
popup('http://www.google.com', 'my-win');
或者稍微抵消
popup('http://www.google.com', 'my-win', 30, 30);
关键是window.screenX/screenLeft为您提供与整个桌面相关的位置,而不仅仅是监视器.
window.screen.left将是您提供所需信息的理想候选人.问题是它在页面加载时设置,用户可以将窗口移动到另一个监视器.
更多研究
这个问题的最终解决方案(除了偏离当前窗口位置)需要知道窗口所在的屏幕尺寸.由于屏幕对象不会随着用户移动窗口而更新,我们需要制作我们的自己检测当前屏幕分辨率的方法.这就是我想出来的
/** * Finds the screen element for the monitor that the browser window is currently in. * This is required because window.screen is the screen that the page was originally * loaded in. This method works even after the window has been moved across monitors. * * @param {function} cb The function that will be called (asynchronously) once the screen * object has been discovered. It will be passed a single argument, the screen object. */ function getScreenProps (cb) { if (!window.frames.testiframe) { var iframeEl = document.createElement('iframe'); iframeEl.name = 'testiframe'; iframeEl.src = "about:blank"; iframeEl.id = 'iframe-test' document.body.appendChild(iframeEl); } // Callback when the iframe finishes reloading, it will have the // correct screen object document.getElementById('iframe-test').onload = function() { cb( window.frames.testiframe.screen ); delete document.getElementById('iframe-test').onload; }; // reload the iframe so that the screen object is reloaded window.frames.testiframe.location.reload(); };
因此,如果您想要始终打开窗口所在的任何监视器左上角的窗口,您可以使用以下内容:
function openAtTopLeftOfSameMonitor(url, winName) { getScreenProps(function(scr){ window.open(url, winName, 'top=0,left=' + scr.left); }) }